The product of something means multiplying the terms together.
(2x+3) (4x^2-5x+6)
Secondly you need to distribute the terms to each other (Think of problems like FOIL)
2x * 4x^2 + 2x(-5x) + 2x * 6 + 3 * 4x^2 + 3(-5x) + 3 * 6
Then you must take into account that some of the numbers are negative. (minus-plus rules!)
2x * 4x^2 - 2x * 5x + 2x * 6 + 3 * 4x^2 - 3 * 5x + 3 * 6
Now is the tricky part of simplifying everything.
2x * 4x^2 = 8x^3
2x * 5x = 10x^2
2x * 6 = 12x
3 * 4x^2 = 12x^2
3 * 5x = 15x
3 * 6 = 18
8x^3 - 10x^2 + 12x + 12x^2 - 15x + 18
Then you group like terms.
8x^3 - 10x^2 + 12x^2 - 3x + 18
8x^2 + 2x^2 - 3x + 18
The trickiest part of this is distributing all of the terms within the parentheses, once you've done that, it's smooth sailing!
Answer:
The answer is 
Step-by-step explanation:
because it grows from 4 units to 6 units or 1.5 times.
Answer:
When you're talking factors, you're talking about some sort of integer; that's because “factors” depends on the concept of divisibility, which are virtually exclusive to integers. When you're talking “greater than”, you're excluding complex numbers (where the concept of ordering doesn't exist) and you're probably assuming positive integers. If you are, then no; no positive integer has factors that are larger than it.
If you go beyond positive numbers, that changes. 0 is an integer, and has every integer, except itself, as factors; since its positive factors are greater than zero, there are factors of zero that are greater than zero. If you extend to include negative numbers, you always have both positive and negative factors; and since all positive integers are greater than all negative integers, all negative integers have factors that are greater than them.
Beyond zero, though, no integer has factors whose magnitudes are greater than its own. And that's a principle that can be extended even to the complex integers
Step-by-step explanation:
Answer:
move the constant to the right hand of the side and change the sign
2x>-0.5-5-5
calculate the difference
2x>-6
divide both sides of the inequality by 2
x>-3
solution X>-3
