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irinina [24]
2 years ago
11

A number is doubled and then increased by seven. The result is seventy-one. What is the original number?

Mathematics
1 answer:
marissa [1.9K]2 years ago
6 0

Answer:

i think its 43

Step-by-step explanation:

2 x X + 7 = 93

substract 7 from both sides then divide both sides by 2

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If x = -5 is one solution of x2 +7x +10, what is the other solution?​
Blababa [14]

Answer:

3

Step-by-step explanation:

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3 years ago
When you multiply a pair of conjugates you get a real number
marusya05 [52]

Answer: The complex conjugate has a very special property. Consider what happens when we multiply a complex number by its complex conjugate. We find that the answer is a purely real number  it has no imaginary part. This always happens when a complex number is multiplied by its conjugate the result is real number.

Real numbers can be positive or negative, and include the number zero. They are called real numbers because they are not imaginary, which is a different system of numbers

Step-by-step explanation: Every complex number has a complex conjugate. The complex conjugate of a + bi is a - bi. For example, the conjugate of 3 + 15i is 3 - 15i, and the conjugate of 5 - 6i is 5 + 6i.

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3 years ago
18. A container of rainwater is evaporating at 1.6
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The answer you are looking for is C
6 0
3 years ago
Read 2 more answers
How many complex zeros does the polynomial function have?<br> f(x)=−3x^6−2x^4+5x+6
REY [17]

one way would be to factor

I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have


it goes like this:

for a polynomial with real coefients, consider f(x)=-3x^6-2x^4+5x+6.

after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have

We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root


to get the negative roots, we evaluate f(-x) and see how many times the root changes

f(-x)=-3x^6-2x^4-5x+6

signs are (-, -, -, +). there was 1 change in sign

so the function has 1 real negative root



a total of 2 real roots


a function of degree n can have at most, n roots


our function is degree 6 so it has 6 roots

if 2 are real, then the others must be complex

6-2=4 so there are 4 complex roots


you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots

7 0
3 years ago
2 less than one-third of the points the panthers scored in algebraic expression
o-na [289]
2-1/3(p) is the answer
7 0
3 years ago
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