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ZanzabumX [31]
3 years ago
6

I NEED ASWERS FAST The question is number 5

Mathematics
1 answer:
alekssr [168]3 years ago
6 0

Answer:

<h2>c. 1056</h2>

100% right answer

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Put these fractions from smallest to greatest<br><br>6/5, 8/15, 1/4
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1/4, 8/15, 6/5
One way to figure this out is to divide the fractions and find which number is bigger
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3 0
4 years ago
Read 2 more answers
1) An i staircase has a 10 inch vertical rise per step to get to the second floor of the house. If the angle of elevation is 30.
bezimeni [28]

Answer:

A)

Each landing is about 17 inches.

B)

The vertical rise from Floor 1 to Floor 2 is about 7 feet.

Step-by-step explanation:

Please refer to the attachment below. (I accidentally wrote 30.30 instead of 30.20. Please ignore that and sorry for any confusion.)

Part A)

So, we want to find the length of \ell.

Note that the angle of elevation, the vertical height, and \ell form a right triangle.

Since the vertical height opposite to our angle is 10, and we want to find the adjacent height, we can use the tangent ratio:

\displaystyle \tan(x^\circ)=\frac{\text{Opposite}}{\text{Adjacent}}

Therefore:

\displaystyle \tan(30.20)=\frac{10}{\ell}

Solve for \ell. Cross-multiply:

\displaystyle \ell\tan(30.20)=10

So:

\displaystyle \ell=\frac{10}{\tan(30.20)}=17.1817...\approx17\text{ inches}

The landing space per step is about 17 inches.

Part B)

We know that there are a total of 12 feet of horizontal space total for each landing.

12 feet is equivalent to (12)(12) = 144 inches.

Since each landing is 17.1817... inches, this means that we have 144/(17.1817...) = 8.38... or about 8 steps.

Since the vertical rise of each step is 10 inches, the vertical rise from the 1st Floor to the second will be 8(10) or 80 inches or 80/12 = 6.666... or about 7 feet.

8 0
3 years ago
Please Help :(
balandron [24]

Answer:

Step-by-step explanation:true

5 0
4 years ago
Solve this sumutaneous equation<br> 2x-5 y=9<br> 3x+4y=2
Alla [95]

Answer:

<h2>x = 2 and y = -1 → (2, -1)</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}2x-5y=9&\text{multipy both sides by 4}\\3x+4y=2&\text{multiply both sides by 5}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}8x-20y=36\\15x+20y=10\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad23x=46\qquad\text{divide both sides by 23}\\.\qquad x=2\\\\\text{put it to the second equation}\\\\3(2)+4y=2\\6+4y=2\qquad\text{subtract 6 from both sides}\\4y=-4\qquad\text{divide both sides by 4}\\y=-1

8 0
3 years ago
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