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Monica [59]
3 years ago
15

What value of x makes the equation below true 6x-7=26

Mathematics
2 answers:
VikaD [51]3 years ago
6 0

Answer:

11/2

Step-by-step explanation:

6x−7=26

Step 1: Add 7 to both sides.

6x−7+7=26+7

6x=33

Step 2: Divide both sides by 6.

x= 11/2

Gwar [14]3 years ago
4 0
6x-7=26
+7 +7
6x=33 (divide both sides by 6)
x= 11/2 or 5.5
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Answer:

\sin C\approx0.85\\\\\cos C \approx0.52\\\\\tan C\approx1.63

Step-by-step explanation:

According to the trigonometric ratios in aright triangle :

\sin x =\dfrac{\text{Side opposite to x}}{\text{Hypotenuse}}\\\\\cos x =\dfrac{\text{Side adjacent to x}}{\text{Hypotenuse}}\\\\\tan x=\dfrac{\sin x}{\cos x}

Given:  ΔBCA ~ ΔSTR

Since , corresponding angles of two similar triangles are equal.

So, ∠C = ∠T                            ...(i)    [Middle letter]

In triangle STR

\sin T=\dfrac{\text{Side opposite to T}}{\text{Hypotenuse}}\\\\=\dfrac{26.4}{30.9}\approx0.85\\\\\cos x =\dfrac{\text{Side adjacent to T}}{\text{Hypotenuse}}\\\\=\dfrac{16.2}{30.9}\approx0.52\\\\\tan T=\dfrac{\sin T}{\cos T}\\\\=\dfrac{0.85}{0.52}\approx1.63  ...(ii)

From (i) and (ii), we have

\sin C\approx0.85\\\\\cos C \approx0.52\\\\\tan C\approx1.63

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Do you still need help?


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What is the simplified form of the following expression? 7(3sqrt2x)-3(3sqrt16x)-3(3sqrt8x)
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Assignment: \bold{Simplify \ Equation: \ 7\left(3\sqrt{2}x\right)-3\left(3\sqrt{16}x\right)-3\left(3\sqrt{8}x\right)}

<><><><><><><>

Answer: \boxed{\bold{3\sqrt{2}x-36x}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Remove Parenthesis (a) = a

\bold{7\cdot \:3\sqrt{2}x-3\cdot \:3\sqrt{16}x-3\cdot \:3\sqrt{8}x}

[ Step Two ] Simplify Equations

\bold{7\cdot \:3\sqrt{2}x: \ 21\sqrt{2}x}

\bold{3\cdot \:3\sqrt{16}x: \ 36x}

\bold{3\cdot \:3\sqrt{8}x: \ 18\sqrt{2}x}

[ Step Three ] Rewrite Equation

\bold{21\sqrt{2}x-36x-18\sqrt{2}x}

[ Step Four ] Add Similar Elements

\bold{21\sqrt{2}x-18\sqrt{2}x=3\sqrt{2}x}

[ Step Five ] Rewrite Equation

\bold{3\sqrt{2}x-36x}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

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