Answer:
Step-by-step explanation: let 2:3:5:8 be 2x,3x,5x,8x respectively .
*angles in a quadrilateral is 360 degree
*2x+3x+5x+8x=360
*18x=360
*x=360/18
*x=20
now substitute x in these:
2x=2x20=40
3x=3x20=60
5x=5x20=100
8x=8x20= 160
so these are the following angles: 40,60,100 and 160
Answer:
319 miles.
Step-by-step explanation:
Answer: t-half = ln(2) / λ ≈ 0.693 / λExplanation:The question is incomplete, so I did some research and found the complete question in internet.
The complete question is:
Suppose a radioactive sample initially contains
N0unstable nuclei. These nuclei will decay into stable
nuclei, and as they do, the number of unstable nuclei that remain,
N(t), will decrease with time. Although there is
no way for us to predict exactly when any one nucleus will decay,
we can write down an expression for the total number of unstable
nuclei that remain after a time t:
N(t)=No e−λt,
where λ is known as the decay constant. Note
that at t=0, N(t)=No, the
original number of unstable nuclei. N(t)
decreases exponentially with time, and as t approaches
infinity, the number of unstable nuclei that remain approaches
zero.
Part (A) Since at t=0,
N(t)=No, and at t=∞,
N(t)=0, there must be some time between zero and
infinity at which exactly half of the original number of nuclei
remain. Find an expression for this time, t half.
Express your answer in terms of N0 and/or
λ.
Answer:
1) Equation given:
← I used α instead of λ just for editing facility..
Where No is the initial number of nuclei.
2) Half of the initial number of nuclei:
N (t-half) = No / 2So, replace in the given equation:
3) Solving for α (remember α is λ)
αt ≈ 0.693
⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ
Answer:
-48/11
Step-by-step explanation:
-2x+5-40-9x-13=0
-11x=40-5+13
-11x=48
x=-48/11
The problem would be written out like this: n/5 + 4 = 16. We would have to subtract 4 from both sides to get n/5 = 12. Then, we multiply both sides by 5 and after that step, you get 60. n = 60.