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Alenkasestr [34]
3 years ago
10

Please help I’m stuck.

Mathematics
1 answer:
Alika [10]3 years ago
8 0

Answer: bro Idk imma try to figure it out

Step-by-step explanation:

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The four angles of a quadrilateral are in the ratio 2:3:5:8. Find the angles
sp2606 [1]

Answer:

Step-by-step explanation: let 2:3:5:8 be 2x,3x,5x,8x respectively .

*angles in a quadrilateral is 360 degree

*2x+3x+5x+8x=360

*18x=360

*x=360/18

*x=20

now substitute x in these:

2x=2x20=40

3x=3x20=60

5x=5x20=100

8x=8x20= 160

so these are the following angles: 40,60,100 and 160

8 0
3 years ago
A truck traveled 232 miles in 4 hours. The truck continued traveling at the same average speed. How many miles,
vlada-n [284]

Answer:

319 miles.

Step-by-step explanation:

4 0
3 years ago
Since at t=0, n(t)=n0, and at t=∞, n(t)=0, there must be some time between zero and infinity at which exactly half of the origin
Airida [17]
Answer: t-half = ln(2) / λ ≈ 0.693 / λ

Explanation:

The question is incomplete, so I did some research and found the complete question in internet.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

Answer:

1) Equation given:

N(t)=N _{0} e^{-  \alpha  t} ← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N_{t-half} =  N_{0} /2 =  N_{0}  e^{- \alpha t}

3) Solving for α (remember α is λ)

\frac{1}{2} =  e^{- \alpha t} 

2 =   e^{ \alpha t} 

 \alpha t = ln(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ




4 0
3 years ago
-2x+5-40-9x - 13 help me please​
Naddika [18.5K]

Answer:

-48/11

Step-by-step explanation:

-2x+5-40-9x-13=0

-11x=40-5+13

-11x=48

x=-48/11

7 0
4 years ago
The quotient of a number and five increased by four is sixteen answer
Anastasy [175]
The problem would be written out like this: n/5 + 4 = 16. We would have to subtract 4 from both sides to get n/5 = 12. Then, we multiply both sides by 5 and after that step, you get 60. n = 60.
3 0
3 years ago
Read 2 more answers
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