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Answer:
Z = -1.789
P value = 0.036807
Step-by-step explanation:
Here
H0: p = 0.85 students will have access to the internet at home
Ha: p < 0.85 students will have access to the internet at home
As per the given data, out of 120 sampled students, 95 have access to internet at home
This is 79.17 % of the total number of sampled students.
The Z values is given by
Substituting the given values, we get -
The sample proportion of 0.7917 is about -1.789 standard errors below the population proportion given in the null hypothesis.
Considering, result is significant at p < .05, the P-Value is .036807.
First 3-digit number divisible by 12 is 108.
Last 3-digit number divisible by 12 is 996.
108 = 12 · 9
996 = 12 · 83
From 108 to 996 are 83 - 9 + 1 = 75 numbers divisible by 12.
108 is the first term of the arithmetic sequence.
996 is the 75th term of the arithmetic sequence.
Use the formula of a sum of terms of an arithmetic sequence:
We have:
Substitute: