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diamong [38]
2 years ago
9

Type the missing number that makes these fractions equal: 42/48=?/24

Mathematics
1 answer:
elixir [45]2 years ago
6 0

Answer:

21

Step-by-step explanation:

cross multiply

42 x 24 = 48x

1008 = 48x

x = 21

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Anyone who knows this mathematic question.to help please. Am giving the brainliest.
Oksana_A [137]
Log of 2x cube - log x = log 16 +log x

Use the identities!

Log 2x square = log 16x
2x square = 16 x
2x sqr - 16x = 0
2x(x-8) = 0
X = 0 or 8
According to logarithms x can’t be 0 so it’s 8
5 0
3 years ago
Write the first five digits of 1/7 in base 9 expression
kaheart [24]

Compare 1/7 to consecutive multiples of 1/9. This is easily done by converting the fractions to a common denominator of LCM(7, 9) = 63:

1/9 = 7/63

2/9 = 14/63

while

1/7 = 9/63

Then 1/7 falls between 1/9 and 2/9, so 1/7 = 1/9 plus some remainder. In particular,

1/7 = 1/9¹ + 2/63.

We do the same sort of comparison with the remainder 2/63 and multiples of 1/9² = 1/81. We have LCM(63, 9²) = 567, and

1/9² = 7/567

2/9² = 14/567

3/9² = 21/567

while

2/63 = 18/567

Then

2/63 = 2/9² + 4/567

so

1/7 = 1/9¹ + 2/9² + 4/567

Compare 4/567 with multiples of 1/9³ = 1/729. LCM(567, 9³) = 5103, and

1/9³ = 7/5103

2/9³ = 14/5103

3/9³ = 21/5103

4/9³ = 28/5103

5/9³ = 35/5103

6/9³ = 42/5103

while

4/567 = 36/5103

so that

4/567 = 5/9³ + 1/5103

and so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/5103

Next, LCM(5103, 9⁴) = 45927, and

1/9⁴ = 7/45927

2/9⁴ = 14/45927

while

1/5103 = 9/45927

Then

1/5103 = 1/9⁴ + 2/45927

so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/45927

One last time: LCM(45927, 9⁵) = 413343, and

1/9⁵ = 7/413343

2/9⁵ = 14/413343

3/9⁵ = 21/413343

while

2/45927 = 18/413343

Then

2/45927 = 2/9⁵ + remainder

so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/9⁵ + remainder

Then the base 9 expansion of 1/7 is

0.12512..._9

8 0
2 years ago
What us tge distributive property if 14+63
artcher [175]
14 + 63 = \boxed{7 (2+9)}



Distributive property is a (b+c) = ab + ac
7 0
3 years ago
Jada sells ground paprika.
dimulka [17.4K]

Answer:

the answer is $200

Step-by-step explanation:

i am taking the khan academy quiz right now

7 0
3 years ago
Read 2 more answers
How are y-intercepts of y=(1/3)^x and y=5(1/3)^x different?
loris [4]
Remark.
The easiest way to do this question is to graph it. Start with that.
The red line is y = (1/3)^x
The blue line is y = 5*(1/3)^x

Comment
The red line's y intercept is (0,1)
The blue line's y intercept is (0,5)

Why
If the x value is 0 then (1/3)^0 = 1
y = (1/3)^0 = 1 * 1 = 1 and for the blue graph
y =  5*(1/3)^0 = 5*1 = 5

In other words, in this set of equations, the 5 makes the y intercept 5 times larger than the 1 in front of y = (1/3)^x

If you have choices, could you please list them? I may be giving you the right answer but not in the form required.

7 0
3 years ago
Read 2 more answers
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