Type the missing number that makes these fractions equal: 42/48=?/24

Mathematics

1 answer:

elixir [45]2 years ago

6 0

Answer:

Step-by-step explanation:

cross multiply

42 x 24 = 48x

1008 = 48x

x = 21

You might be interested in

Hurryyy Plzzz!!

Minchanka [31]

Side angle side the answer hope that helps

6 0

2 years ago

What is the value of the expression? <br> 5(-4)-(10+5)

andrew-mc [135]

Answer:

Step-by-step explanation:

4 0

2 years ago

Sanja made a hole-in-one on the sixth hole of miniature golf 8 times and missed it 4 times. If Sanja attempts 24 more holes-in-o

hram777 [196]

Answer:

16 holes in ones

Step-by-step explanation:

I just did the guiz and got that one right

7 0

3 years ago

Read 2 more answers

Given: Ray BC bisects angle ABD.

natita [175]

Congruent is the same size and same shape. When a ray bisects an angle, the two newly created angles will be congruent, since the ray went right in the middle of the first angle (so in this case, ABC and DBC will be congruent)

4 0

3 years ago

Read 2 more answers

A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest

faltersainse [42]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73$

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396$

add both amounts, and that's her investment for the 11 years.

7 0

3 years ago