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trasher [3.6K]
3 years ago
5

Solve 2x^2 + x - 4= 0. x2 + = 0 DONE

Mathematics
1 answer:
inessss [21]3 years ago
8 0

\\ \sf\longmapsto 2x^2+x-4=0

\\ \sf\longmapsto 2x^2+x=4

\\ \sf\longmapsto 8(2x^2+x=4)

\\ \sf\longmapsto 16x^2+8x=32

\\ \sf\longmapsto (4x)^2+2(4x)(1)=32

\\ \sf\longmapsto 4x^2+2(4x)(1)+1^2=32+1^2

\\ \sf\longmapsto (4x+1)^2=33

\\ \sf\longmapsto 4x+1=\pm\sqrt{33}

\\ \sf\longmapsto 4x=-1\pm\sqrt{33}

\\ \sf\longmapsto x=\dfrac{-1\pm\sqrt{33}}{4}

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