A student used a compass and a straightedge to construct
title="\overline{CE}" alt="\overline{CE}" align="absmiddle" class="latex-formula"> in ABC. Which statement must always be true for this construction?(1) ∠CEA, ∠CEB(2) ∠ACE, ∠BCE(3) 
(4) 
1 answer:
Answer:
2) ∠ACE ≅ ∠BCE
Step-by-step explanation:
Considering the complete question attached in Figure below, geometry shows that ∠ACB is bisected into two angles ∠ACE and ∠BCE and we know that bisection means to divide an angle into two equal angles. According to this the resultant angles ∠ACE and ∠BCE must be equal and congruent.
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The z-score of the considered newborn having 4,000 g weight is
If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.
If we have
(X is following normal distribution with mean and standard deviation
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then it can be converted to standard normal distribution as
(Know the fact that in continuous distribution, probability of a single point is 0, so we can write
Also, know that if we look for Z = z in z tables, the p value we get is
For the considered case, the statement in the problem is missing the mean weight of the newborn and standard deviation of the data set of weights of newborn.
Thus, for them, we can consider variables in place of their actual values.
Let we have:
- X = weights of newborns for some considered system (in grams)
= mean weight of newborns (in grams)
= standard deviation of the data set of weights of newborns
Then, the z-score for X = 4000 is
Thus, the z-score of the considered newborn having 4,000 g weight is
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