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MatroZZZ [7]
2 years ago
14

Pleaseeee helpppppppp its due now

Mathematics
1 answer:
Kisachek [45]2 years ago
7 0

Answer:

find AC and BC then check multiply their slopes

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Solve for x please. First correct answer I’ll mark as brainliest
katrin [286]

Answer:

x=7

Step-by-step explanation:

6 0
2 years ago
How to regroup 378x6. pls help mev
olga55 [171]
It is 2,268!!! Thts the answer
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3 years ago
A quarterback throws a pass from the 10-yard line, 2 yards from the sideline. A wide received catches the pass on the 64-yard li
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2 years ago
The original price of a 2018 Honda Shadow to the dealer is $17,715, but the dealer will pay only $16,985 after rebate. If the de
vitfil [10]

Answer:

The final price to be paid after the 2% discount has been made will be $ 16,645.30.

Step-by-step explanation:

Since there is a 2% discount on the price of the Honda Shadow in the event that the dealer pays Honda within 15 days, and that after a rebate the price of the vehicle is $ 16,985, to obtain the value of the discount and the final amount to be paid must be calculated as follows:

16,985 x 2/100 = X

33,970 / 100 = X

339.70 = X

Thus, the discount to be made will be $ 339.70, with which the final price to be paid after the 2% discount has been made will be $ 16,645.30.

4 0
3 years ago
The miles-per-gallon rating of passenger cars is a normally distributed random variable with a mean of 33.8 mpg and a standard d
EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.

It is provided that X\sim N(\mu=33.8,\ \sigma^{2}=3.5^{2}).

Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})

                   =P(Z>1)\\\\=1-P(Z

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

7 0
2 years ago
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