Answer:
Video result for Let F(x) = 2x2 + x - 3 and g(x) = x - 1. f(x) g(x) Find and state its domain. Answers: X - 1; domain is the set of all real numbers (x-1)/(2x + 3) ; domain is the set of all real numbers except-(3/2) 2x + 3; domain is the set of all real numbers except 16:39
How to find the range of a function (video)
Khan Academy · Khan Academy
Video result for Let F(x) = 2x2 + x - 3 and g(x) = x - 1. f(x) g(x) Find and state its domain. Answers: X - 1; domain is the set of all real numbers (x-1)/(2x + 3) ; domain is the set of all real numbers except-(3/2) 2x + 3; domain is the set of all real numbers except 18:07
Domain and range of quadratic functions (video)
Khan Academy · Khan Academy
Video result for Let F(x) = 2x2 + x - 3 and g(x) = x - 1. f(x) g(x) Find and state its domain. Answers: X - 1; domain is the set of all real numbers (x-1)/(2x + 3) ; domain is the set of all real numbers except-(3/2) 2x + 3; domain is the set of all real numbers except 11:47
Domain of a radical function (video)
Khan Academy · Khan Academy
Video result for Let F(x) = 2x2 + x - 3 and g(x) = x - 1. f(x) g(x) Find and state its domain. Answers: X - 1; domain is the set of all real numbers (x-1)/(2x + 3) ; domain is the set of all real numbers except-(3/2) 2x + 3; domain is the set of all real numbers except 14:57
Determining whether values are in domain of function (video)
Khan Academy · Khan Academy
Step-by-step explanation:
3 gallons is less because there are 12quarts
Do you have choices?
The most simplified expression that is equal is
-27x-28
If one side of a triangle is 15 and another side is 20, then the third side
can be any length between 5 and 35. There are an infinite number of
possible triangles.
IF it happens to be a RIGHT triangle AND side 'a' and side 'b' happen
to be its legs, then the length of the third side is 25. But you didn't
mention any of those details.
The area of the entire sector of DEF = 60 / 360 * PI * radius^2
sector area = 1 / 6 * 3.14159265... * 20^2
sector area =
<span>
<span>
<span>
209.4395102393
</span>
</span>
</span>
segment area = sector area - triangle DEF Area
triangle DEF Area = (1/2) * 20 * sine 60 * 20
triangle DEF Area = (1/2) * 0.86603 * 400
triangle DEF Area = <span><span><span>(1/2) * 346.412
</span>
</span>
</span>
triangle DEF Area =
<span>
<span>
<span>
173.206
</span>
</span>
</span>
segment area = <span>
<span>
209.4395102393
</span>
-173.206
</span>
segment area =
<span>
<span>
<span>
36.2335102393
</span>
</span>
</span>
segment area =
36.23 m
Source:
http://www.1728.org/circsect.htm
