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Scrat [10]
3 years ago
5

One leg of an isosceles right triangle measures 5 inches. Rounded to the nearest tenth, what is the approximate length of the hy

potenuse? 2.5 inches 5.0 inches 7.1 inches 9.8 inches
Mathematics
2 answers:
Zolol [24]3 years ago
7 0

Answer:  7.1 inches

Step-by-step explanation:

Given: One leg of isosceles right triangle = 5 inches

Since in isosceles right triangle , two sides have same side length , therefore the length of the other leg should be 5 inches.

Let H be the hypotenuse of the isosceles right triangle

Now, by Pythagoras Theorem , we have

H^2=5^2+5^2=25+25=50\\\\\Rightarrow\ H=\sqrt{50}=5\sqrt{2}\\\\\Rightarrow\ H==5\times(1.41421356237)\\\\\Rightarrow\ H==7.07106781187\approx7.1\ inches

Hence, the approximate length of the hypotenuse = 7.1 inches

PSYCHO15rus [73]3 years ago
6 0
The answer is 7.1 inches. hope this helped
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Answer:

COP: 2X

Step-by-step explanation:

K= Y/X

K= 4/2

K= 8/4

K= 12/6

K=16/8

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A flagpole broke in a storm. It was originally 81 8181 feet tall. 28 2828 feet are still sticking straight out of the ground, wh
solong [7]

Answer:

The end of the flagpole is 50.79 ft away from the base of the pole.

Step-by-step explanation:

The problem is represented by the diagram below.

The broken flagpole forms the shape of a right angled triangle. We need to find one of the sides of the triangle, the adjacent (x).

The hypotenuse is the broken part of the flagpole (53 ft), while the opposite is the part of the flagpole that is still stuck to the ground (28 ft).

Using Pythagoras theorem, we have that:

hyp^2 = adj^2 + opp^2

=> 53^2 = x^2 + 28^2

3364 = x^2 + 784\\\\=> x^2 = 3364 - 784\\\\x^2 = 2580\\\\x = \sqrt{2580}\\ \\x = 50.79 ft

The end of the flagpole is 50.79 ft away from the base of the pole.

7 0
3 years ago
B / -7 = 4<br><br> solve question correctly
Shkiper50 [21]

Answer:

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Step-by-step explanation:

If this helps you mark as brainlist.!

4 0
3 years ago
Read 2 more answers
The radius of a circle is 4 m. Find its area in terms of <br> π<br> π.
wlad13 [49]

Answer:

16π

Step-by-step explanation:

Given:

\text{Radius of circle}: 4 \ \text{m}

<u>Formula:</u>

\text{Area of circle} = \pi r^{2}

Replace the radius in the formula:

\implies \text{Area of circle} = \pi (4)^{2}

Evaluate the area:

\implies \text{Area of circle} = \pi (4)(4)

\implies \text{Area of circle} = 16\pi

Since the question says to determine the area in terms of π, the final answer is 16π.

8 0
2 years ago
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