Answer:
in table data from a survey about the amount of time students spend doing homework each week. The students were either in college or in high school: High Low Q1 Q3 IQR Median Mean σ
College 50 5 7.5 15 7.5 11 13.8 6.4
High School16 0 9.5 14.5 5 13 10.7 5.3 Both spreads are best described with the standard deviation.
Step-by-step explanation:
Can you rephrase it? (maybe write it out in numbers?)
4.
b^-2-x^-2/b^-1+x^-1
b^-2/b^-1=b^-1
x^-2/x^-1=x^-1
As a result, the simplest form is:
b^-1-x^-1. Hope it help!
To find the answer first find the base number or 1% of $188 which is 1.88. Next find what percent is asking for 25% so multiply by 25 1.88 which is 47 so 47-188 = 141 this is one way to do it
A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.
There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.
The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.
However, if the question were to say "and," we would multiply the two probabilities.
Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).


Now we can add them together.

This cannot be simplified further, so the probability is 17 in 52, or 33%.
hope this helps!