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SVEN [57.7K]
2 years ago
13

HELP!!! PLEASE!!!!!!!!!!

Mathematics
2 answers:
faust18 [17]2 years ago
8 0
Hi! You have to put the protractor on the middle dot to figure it out. I can’t figure it out because of that. Good luck!
sveta [45]2 years ago
6 0
Sorry but I see that you can use the “interactive protractor” and see how many degrees the angle is. But all I can tell you is that it’s an acute angle
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The table below shows data from a survey about the amount of times students spend doing homework each week. The students were ei
Anna007 [38]

Answer:

in table data from a survey about the amount of time students spend doing homework each week. The students were either in college or in high school: High Low Q1 Q3 IQR Median Mean σ

College 50 5 7.5 15 7.5 11 13.8 6.4

High School16 0 9.5 14.5 5 13 10.7 5.3 Both spreads are best described with the standard deviation.

Step-by-step explanation:

8 0
2 years ago
When 2 less than 3 lots of a number is doubled the result is 5
Vitek1552 [10]
Can you rephrase it? (maybe write it out in numbers?)
4 0
3 years ago
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How do I put this rational expression in simplest form? Steps please!!!!
Cloud [144]
4.
b^-2-x^-2/b^-1+x^-1

b^-2/b^-1=b^-1
x^-2/x^-1=x^-1
As a result, the simplest form is:
b^-1-x^-1. Hope it help!
8 0
3 years ago
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A coat regularly priced at $188 is on sale for 25% off. what is the sale price
Allushta [10]
To find the answer first find the base number or 1% of $188 which is 1.88. Next find what percent is asking for 25% so multiply by 25 1.88 which is 47 so 47-188 = 141 this is one way to do it
3 0
3 years ago
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If a single card is drawn from a standard 52-card deck, what is the probability that it is an ace or a spade?
klasskru [66]

A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.

There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.

The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.

However, if the question were to say "and," we would multiply the two probabilities.

Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).

\frac{1}{4} -- > \frac{13}{52}

\frac{1}{13} -- > \frac{4}{52}

Now we can add them together.

\frac{13}{52} + \frac{4}{52} = \frac{13+4}{52} = \frac{17}{52}

This cannot be simplified further, so the probability is 17 in 52, or 33%.

hope this helps!

7 0
1 year ago
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