Answer: the probability that a person who tested positive actually has TB is 0.64
Step-by-step explanation:
lets say
T : has tuberculosis
+ : test results +ve
- : test result is -ve
so given that
P(+ITc) = 0.008
P(-ITc) = 0.15
P(T) = 50/3000 = 1/60
P(Tc) = 1 - P(T) = 1 - 1/60 = 59/60
Now required probability
= P(TI+)
P(T∩+) / P(+)
= P(T) × P(+IT) / [[P(T) × P(+IT)] + [(P(Tc) × P(+ITc)]
= P(T) × {1-P(-IT)] / [[P(T) × [1-P(-IT)] + [(P(Tc) × P(+ITc)]
WE SUBSTITUTE
= { 1/60 × (1-0.15) } / [1/60 × (1 - 0.15)] + [(59/60) × 0.008]
= (0.0167 × 0.85) / [(0.0167 × 0.85) + (0.9833 × 0.008)]
= 0.01417 / 0.02206
= 0.6423 ≈ 0.64
∴ the probability that a person who tested positive actually has TB is 0.64
Answer:
D(t) = 485t + 940
Step-by-step explanation:
D(t) = ?
We are told that the flight itself is 940 miles. This is a constant value, it will not change.
D(t) = ? + 940
Following this, we are also told the plane travels at 485 miles per hour. MPH usually indicates multiplication. 485 miles <em>per</em> each of hour (time here is represented by the variable t). 485t
D(t) = 485t + 940
Answer:
D
Step-by-step explanation:
yellow was picked more times then green so the percent would be more then 50.
24h + 18f = 88.50
28h + 9f = 88.25.....multiply by -2
---------------------
24h + 18f = 88.50
-56h - 18f = - 176.50 (result of multiplying by -2)
--------------------add
-32h = - 88
h = -88/-32
h = 2.75 <===
Answer:
Step-by-step explanation:20
