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elena-14-01-66 [18.8K]
3 years ago
8

HELP MATH TEST solve the following equation for p 4.8p = 16.8

Mathematics
2 answers:
katen-ka-za [31]3 years ago
7 0
The answer is 3.5 :)
Tju [1.3M]3 years ago
4 0

Answer:

3.5

Step-by-step explanation:

16.8/4.8= 3.5

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y=10

Step-by-step explanation:

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Expressions are equivalent???
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only the first option is equivalent

Step-by-step explanation:

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Find the exact circumference of a circle with the given radius. 5 inches C = 2.5π in. 10π in. 25π in.
docker41 [41]
The circumference, C, of a given circle may be calculated through the equation,
         
                                   C = 2πr

where r is the radius. 

Substituting the known values from the given in this item,
                                    C = 2(π)(5 in)
                                    <em>C = 10π in</em>

Thus, the answer is this item is the second choice. 
5 0
3 years ago
Triangles 1 and 2 have the angle measures
lawyer [7]

Answer:

C

Step-by-step explanation:

Both triangles have three angles of the same value.

Remember that the angles in all triangles add up to 180°.

Let's use that to find out the unknown angles.

For the first triangle:

180 - 82 - 43 = 55°

55° is also in the second triangle.

Let's check with the second triangle:

180 - 82 - 55 = 43°

43° is also in the first triangle.

Therefore, both triangles are similar as the angles in both triangles are the same - 82°, 43° and 55°.

Hence, C.

7 0
3 years ago
What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

4 0
3 years ago
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