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azamat
3 years ago
5

9

Mathematics
1 answer:
zlopas [31]3 years ago
8 0

Answer:

m = 1/2

Step-by-step explanation:

The given equation of line is :

2x – 4y = 9 ..(1)

We need to find the slope of the line. The general equation of a line is given by :

y = mx + c ..(2)

Where

m is the slope of line

Equation (1) can be rearranged as follow :

-4y = 9-2x

4y = -9+2x

or

4y = 2x-9

Divide both sides by 4.

\dfrac{4y}{4} = \dfrac{2x}{4}-\dfrac{9}{4}\\\\y=\dfrac{1}{2}x+(\dfrac{-9}{4}) ..(3)

Now comparing equation (2) and (3) we get :

m=\dfrac{1}{2}

So, the slope of the line is 1/2.

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For the following right triangle, find the side length x. Round your answer to the nearest hundredth.
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3 years ago
Question 2:
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With the frequecy distribution shown in the 50 cities of pakistan,

  • range = 18
  • mean = 18.1
  • median = 19.8333
  • mode = 19.125
  • kurtosis = 2.7508
  • Standard deviation = 3.75

<h3>How to find the Range</h3>

= highest value - lowest value

= 26.5 - 8.5

= 18

<h3>How to find the mean</h3>

= ∑ f x / ∑ f

= ∑ f x / N

= 905 / 50

= 18.1

median

= lower limit + ( N/2 - C ) * h / ( frequency of the class interval )

C = cumulative frequency preceeding to the median class frequency

h = class interval

= 18.5 + ( 50 / 2 - ( 5 + 12 ) ) * 3 / 18

= 18.5 + 1.3333

= 19.8333

<h3>How to find the mode</h3>

The mode is the value with the highest frequency occurence. This is under class 18 - 20

mode = lower limit + ( ( f1 - f0 ) / (2*f1 - f0 - f2 ) ) * h

f1 = fequency of the modal class

f0 = freqency of the preceeding modal class

f2 = frequency of the next modal class

h = class interval

= 18.5 + ( ( 18 - 12 ) / (2 * 18 - 12 - 8 )  ) * 3

= 18 + ( 0.375 ) * 3

= 19.125

<h3>How to find the standard deviation </h3>

= sqrt ( 1 / N ∑ f ( x - x' )^2 )

= sqrt (1  / 50 * 706.5

= 3.7589

<h3>How to solve for relative dispersion </h3>

=  standard deviation / mean

= 3.7589 / 3

= 1.2530

<h3>What is the variance? </h3>

= ( standard deviation )^2

= ( 3.7589 )^2

= 14.1293

<h3>How to solve for kurtosis</h3>

=  ∑ f ( x - x' )^4 / ( N * ( standard deviation )^4 )

= 27459.405 / ( 50 * 3.7589^4 )

= 2.7509

Read more on frequency distribution here: brainly.com/question/1094036

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