9

Mathematics

1 answer:

zlopas [31]2 years ago

8 0

Answer:

m = 1/2

Step-by-step explanation:

The given equation of line is :

2x – 4y = 9 ..(1)

We need to find the slope of the line. The general equation of a line is given by :

y = mx + c ..(2)

Where

m is the slope of line

Equation (1) can be rearranged as follow :

-4y = 9-2x

4y = -9+2x

4y = 2x-9

Divide both sides by 4.

$\dfrac{4y}{4} = \dfrac{2x}{4}-\dfrac{9}{4}\\\\y=\dfrac{1}{2}x+(\dfrac{-9}{4})$ ..(3)

Now comparing equation (2) and (3) we get :

$m=\dfrac{1}{2}$

So, the slope of the line is 1/2.

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anyanavicka [17]

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Step-by-step explanation:

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4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25

jarptica [38.1K]

Answer with explanation:

$\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}$

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

$=e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}$

Multiplying both sides by Integrating Factor

$x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)$