Answer:
im pretty sure the distance is across the y and x axis
Step-by-step explanation:
This question is a piece-o-cake if you know the formulas for the area and volume of a sphere, and impossible of you don't.
Area of a sphere = 4 π R² (just happens to be the area of 4 great circles)
Volume of a sphere = (4/3) π R³
We know the area of this sphere's great circle, so we can use the
first formula to find the sphere's radius. Then, once we know the
radius, we can use the second formula to find its volume.
Area of 4 great circles = 4 π R²
Area of ONE great circle = π R²
225 π cm² = π R²
R² = 225 cm²
R = √225cm² = 15 cm .
Now we have a number for R, so off we go to the formula for volume.
Volume = (4/3) π R³
= (4/3) π (15 cm)³
= (4/3) π (3,375 cm³)
= 14,137.17 cm³ (rounded)
This answer feels very good UNTIL you look at the choices.
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I've gone around several loops and twists trying to find out what gives here,
but have come up dry.
The only thing I found is the possibility of a misprint in the question:
If the area of a great circle is 225π cm², then the sphere's AREA is 900π cm².
I'm sure this is not the discrepancy. I'll leave my solution here, and hope
someone else can find why I'm so mismatched with the choices.
What do the up arrows mean? I may be able to help if you tell me.
You first have to find the slope using the slope formula. That looks like this with our values:
. So the slope is -1/8. Use one of the points to first write the equation in y = mx + b form. We have an x and a y to use from one of the points and we also have the slope we just found. Filling in accordingly to solve for b gives us
and
. Adding 5/8 to both sides and getting a common denominator gives us that
. Writing our slope-intercept form we have
. Standard form for a line is Ax + By = C...no fractions allowed. So let's get rid of that 8 by multiplying each term by 8 to get 8y = -x - 11. Add x to both sides to get it into the correct form: x + 8y = -11
The domain of a(x) is all of R. The domain of b is the range where
. We can calculate the composition boa by changing in the expression for b, every x with a(x). Hence, boa(x)=
=
. Again for a function with a root to be defined, we need that the expression under the square root has to be positive. Hence, 3x-3
0.Thus, the set where this holds is
. This is also the domain of the function boa(x).
