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2 years ago

Identify the median and the lower quartile for this box plot 16,16.5,15.5,

Mathematics

2 answers:

MArishka [77]2 years ago

8 0

The median should be 16

sertanlavr [38]2 years ago

8 0

Answer:

The median is should be 16 I think

Step-by-step explanation:

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What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

3 years ago

2. What is the experimental probability of rolling a 4

boyakko [2]

Answer:

1. 40%

2. The theoretical probability is 3% greater than the experimental probability.

Step-by-step explanation:

We are informed that a number cube is rolled 20 times and the number 4 is rolled 8 times. The experimental probability of rolling a 4 is;

(the number of times a 4 was rolled)/(total number of rolls)

8/20 = 0.4

0.4*100 = 40%

The experimental probability of obtaining at least one tails, one or more tails, is represented in mathematical notation as;

P(HT or TH or TT)

The above events are mutually exclusive, thus;

P(HT or TH or TT) = P(HT) + P(TH) + P( TT)

= (22+34+16)/(28+22+34+16)

= 0.72 = 72%

On the other hand, the theoretical probability of obtaining at least one tails,

P(HT or TH or TT) = 3/4

= 75%

This is because there is at least one tail in 3 out of 4 possible outcomes.

Therefore, it is true to say that the theoretical probability is 3% greater than the experimental probability.

6 0

2 years ago

Read 2 more answers

What is the range of the function f(x) = |x| – 3?

Likurg_2 [28]

Why not draw the graph of y=|x|? It has a v-shape, and the vertex is at (0,0).

The graph of f(x) = |x| - 3 looks exactly the same, EXCEPT that the whole graph of |x| is shifted 3 units downward. The smallest value that y can have is therefore -3.

Can you now figure out the range of f(x)?

3 0

3 years ago

7x-3=4x+3 < Answer Please

USPshnik [31]

Answer:

2! Thank it if it was helpful :D

Step-by-step explanation:

7x-4x=3+3

3x=6

x=2

8 0

2 years ago