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loris [4]
2 years ago
13

What is the answer to 4×...=120

Mathematics
2 answers:
yawa3891 [41]2 years ago
5 0

4x30=120

There you go



Ad libitum [116K]2 years ago
4 0

The answer is 30

you can find the answer by doing 120÷4

which equals 30

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2x^5 + 4x^4 – x^3 - x^2 + 7 is divided by 2x^2 - 1.
mixer [17]

Answer: 11

Step-by-step explanation: 2x^5 + 4x^4 – x^3 - x^2 + 7= 11

2x^2 - 1= 1

2x^5 + 4x^4 – x^3 - x^2 + 7 is divided by 2x^2 - 1.=11

4 0
3 years ago
Find the solution to the system of equations.
Rzqust [24]

Answer:

(4, 1).

Step-by-step explanation:

The solution is the coordinates of the points where the 2 lines intersect.

That is where x = 4 and y = 1.

4 0
2 years ago
A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s heigh
Nataly_w [17]

Answer D). 9 ft is correct

Height of the ball at a horizontal distance of 10 feet is 9 ft

Step-by-step explanation:

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s height (y).

Y(x) = -0.02x^{2} +0.8x+3

Question asked is " What will be height (Y) of the ball when X=10 ft "

Simply putting value of X in given equation

we get,

Y(x) = -0.02x^{2} +0.8x+3

Y(x) = -0.02(10)^{2} +0.8(10)+3

Y(x) = -0.02(100)} +8+3

Y(x) = -2 +8+3

Y(x) = 9

<em>Therefore,</em> Height of the ball at a horizontal distance of 10 feet is 9 ft

Answer D.  9 ft is correct

6 0
3 years ago
If the length of a cuboid is 60cm and width 40cm and its surface area is 14800cm² find its height
kherson [118]
Formula of surface area of cuboid = 2(lb+bh+lh) . Surface area of cuboid is 14800cm^2 (Given) then 14800 = 2(60*40+40*Height+Height*60) 14800= 2(2400+40*H+H*60) 14800= 4800+80*2H+2H*60 14800= 4880*4H*60 14800/4880*60= 4H
14800/292800=4H
7400/146400=4H
3700/73200=4H
1850/36600=4H
925/18300=4H
185/3660=4H
37/732=4H
37/732*4=H
37/2928=H
H= 79.1351351
3 0
2 years ago
Read 2 more answers
00:00
Aleks04 [339]

Answer:

Figure A is a  translation of Figure 1

hope it helps...

7 0
2 years ago
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