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Natalka [10]
3 years ago
10

Someone please help me on this geometry test

Mathematics
1 answer:
Kamila [148]3 years ago
4 0

Answer:

A.

Step-by-step explanation:

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The lengths of the three sides of a triangle (not necessarily a right triangle) are 3.16 meters, 8.25 meters and 10.4 meters. wh
Dafna1 [17]
For non-right triangles you must use the "Law of Cosines"  and then, the "Law of Sines" to solve this<span>.

a= </span> 8.25m<span>
b=</span> 10.4m<span>
c= </span>3.16m
∠<span>A= UNKNOWN
</span>∠<span>B= UNKNOWN
</span>∠<span>C=UNKNOWN

Law of Cosines:
c</span>²= a²+b²-2abCos(C)
(3.16)²= (8.25)²+(10.4)²- 2(8.25)(10.4)(cos(C))
9.9856 = 68.0625 + (108.16) - (171.6)(cos(C)
9.9856 = 176.2225- 171.6 cos C
-166.2369=  - (171.6(cosC))
cosC= 0.968746503
<span>Take the inverse cosine of that to get the measure of angle C
</span>∠C= 15.95813246°
<span>
Now Use law of sines to find </span>∠B:
\frac{10.4}{Sin(B)} = \frac{3.16}{sin(15.96)}
\frac{10.4}{Sin(B)} =12.73922
10.4 =12.73922115(sinB)
sinB= 0.816276439
(take the inverse sine to get the measure of ∠B)
∠B= 60.8040992°
<span>

Answer:
The angle measures approximately 60.80</span>°.<span>



</span>

7 0
3 years ago
What are m&lt;1 and m&lt;2?
spin [16.1K]

Answer:

m∠1=114

m∠2=66

Step-by-step explanation:

First, let's find the m∠2

∠2 is inside a triangle, and the angles in a triangle must add to 180 degrees.

So,

55+59+∠2=180

Add 55 and 59

114+∠2=180

We are trying to find ∠2, so we have to get it by itself.

114 is being added on to ∠2. To undo this, subtract 114 from both sides.

114-114+∠2=180-114

∠2=66

Now we know the m∠2, but we still have to find m∠1.

∠2 and ∠1 are on a straight line. This means they are supplementary angles and add to 180 degrees.

∠1+∠2=180

We know that ∠2 is 66, so we can substitute it in.

∠1+66=180

66 is being added onto ∠1. To undo this, subtract 66 from both sides.

∠1+66-66=180-66

∠1=114

6 0
3 years ago
Read 2 more answers
A quadrilateral ABCD has the area 10 square feet. After a dilation with a scale factor of 3, find the area of quadrilateral A'B'
gtnhenbr [62]

10 x 3^2

= 10 x 9

= 90

5 0
3 years ago
How to solve 2(c 3)=c-13?
kiruha [24]
First we substitute, what that means in here is that 2(c +3)
Or minus I can't see the sign but what we do is we substitute 2 with c so that becomes 2c and 2 with 3 and that becomes 6 which gives us 2c + 6 = c-13
Now we can either add 13 on both sides or subtract 6 on both sides, we can do this because they are like terms even if they are negative because they don't have any variable behind it. We will add 13 because we do the opposite of the sign you are solving some get 2c + 19 = c now we subtract 2c on both sides and we get 19 = -1c and at the end we divide -1 on both side and we get -19 = c or
c = -19.
4 0
3 years ago
The equation of line p is y = x − 1 .
NeX [460]

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line p is

y = x - 1

Comparing with the slope intercept form, slope = 1

If two lines are parallel, it means that they have the same slope. Therefore, the slope of line q passing through (- 2, 8) is 1

To determine the y intercept, we would substitute m = 1, x = - 2 and

y = 8 into y = mx + c. It becomes

8 = 1 × - 2 + c

8 = - 2 + c

c = 8 + 2 = 10

The equation becomes

y = x + 10

6 0
4 years ago
Read 2 more answers
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