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nignag [31]
3 years ago
10

During the last week of the semester, students at a certain college spend on the average 4.2 hours using the school’s computer t

erminals with a standard deviation of 1.8 hours. For a random sample of 36 students at that college, find the probabilities that the average time spent using the computer terminals during the last week of the semester is a) At least 4.8 hours (Draw the bell curve) b)
Mathematics
1 answer:
matrenka [14]3 years ago
4 0

Answer:

0.97725

Step-by-step explanation:

Given :

Population mean, μ = 4.2

Population standard deviation, σ = 1.8

Sample size, n = 36

Obtain the Zscore of x = 4.8

Zscore = (x - μ) ÷ (σ / √n)

Zscore = (4.8 - 4.2) ÷ (1.8 / √36)

Zscore = 0.6 ÷ 0.3

Z = 2

Hence,

P(Z ≤ 2)

Using the Z probability calculator :

P(Z ≤ 2) = 0.97725

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Use the expression to complete the statements.

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________ is the  power .

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A ______ is another way to write

Answer:

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10 is the power

(0.5)^{10\\ = (\frac{1}{2})^{10} -- another way to write

Step-by-step explanation:

Given

(0.5)^{10\\

Required

Fill ion the gaps

(0.5)^{10\\ is pronounced as; 0.5 raise to the power of 10

From the above statement, we can deduce the following:

0.5 is the base

10 is the power

Lastly, another way to write (0.5)^{10\\

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Hence:

(0.5)^{10\\ = (\frac{1}{2})^{10}

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