Instead of using the quotient rule, you can first expand <em>y</em> :
<em>y</em> = (4<em>x</em> - 1)^2 / <em>x</em> ^2 = (16<em>x</em> ^2 - 8<em>x</em> + 1) / <em>x</em> ^2 = 16 - 8/<em>x</em> + 1/<em>x</em> ^2
Then the derivative is
d<em>y</em>/d<em>x</em> = -8/<em>x</em> ^2 - 2/<em>x</em> ^3
The tangent to the curve at (-1, 25) then has a slope or gradient of
d<em>y</em>/d<em>x</em> = -8/(-1)^2 - 2/(-1)^3 = -6
I think it’s Gonna be A. 15%
Answer:
Step-by-step explanation:
This is a two tailed test for comparison of two variances at 2% significance level

deg of freedom = 7
F statistic = 
p value = 0.4496
1. State the decision rule for 0.02 significance level. (Round your answer to 1 decimal place.) Reject H0 if F >10.4555
2.F=2.041
3. _Accept_________H0. There is __no significant____ in the variations of the two populations