To solve this equation there are many ways you can do to solve. One way is to simply substitute one variable for another.
5x = 5y - 25
X = y - 5
10y = 42 + 2x
10y = 42 + 2(y - 5)
10 y = 42 + 2y - 10
8y = 32
Y = 4.
X = y - 5
X = 4 - 5
X = -1.
P(X,y) = P(-1,4). This would be the solution or the point where they would intersect.
Answer:
la respuesta es 38560
Step-by-step explanation:
<u><em>Answer:</em></u>
Density of jam = 11.35 kg/m³
<u><em>Explanation:</em></u>
<u>1- Getting the mass of the jam:</u>
<u>We are given that:</u>
Jam is put in 6 jars
the weight of one empty jar = 200 grams
<u>Therefore: </u>
weight of 6 empty jars = 6 * 200 = 1200 grams
<u>We are also given that:</u>
Weight of all jars filled with jam is 5400 grams
<u>Therefore:</u>
mass of jam = total mass of jam and jars - mass of 6 empty jars
mass of jam = 5400 - 1200
mass of jam = 4200 grams
<u>2- Getting the volume of the jam:</u>
We are given that the 6 jars had a total volume of 0.37 m³ and that they were completely filled with jam
<u>This means that:</u>
Volume of jam = 0.37 m³
<u>3- Getting the density of jam:</u>
<u>Density can be calculated using the following rule:</u>
![Density = \frac{mass}{volume}](https://tex.z-dn.net/?f=Density%20%3D%20%5Cfrac%7Bmass%7D%7Bvolume%7D)
<u>We have:</u>
Mass of jam = 4200 grams = 4.2 Kg
Volume of jam = 0.37 m³
<u>Therefore:</u>
![Density = \frac{4.2}{0.37} = 11.35 kg/m^3](https://tex.z-dn.net/?f=Density%20%3D%20%5Cfrac%7B4.2%7D%7B0.37%7D%20%3D%2011.35%20kg%2Fm%5E3)
Hope this helps :)
Answer:
Step-by-step explanation:
It's soo hard