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3 years ago

If you throw an apple towards the sky why its going up in spite of gravitational pull? .

Physics

1 answer:

Paul [167]3 years ago

4 0

Answer:

due to tension force acting against gravitational pull

Explanation:

hope this somewhat helps :)

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Engineers can determine properties of a structure that is modeled as a damped spring oscillator, such as a bridge, by applying a

Kazeer [188]

The value of spring constant and the oscillator's damping constant is

K= 6605.667008, b= 0.002884387

Explanation:

For Weakly damping spring oscillator

K/m = W_0^2 (at resonance)

K= mW_0^2

=0.206 * ( 2π * 28.5) ^2

=0.206 * (2π)^2 * (28.5)^2

K= 6605.667008

F = - bV

b= -F/V = -F/ -W_0 * m

=F/W_0 * m

= 0.438N / 2π * 28.5 * 0.848

b= 0.002884387

8 0

3 years ago

Three identical lights are connected in series to a 12V battery. How does the brightness of each light compare?

kodGreya [7K]

Answer: They are identical brightness

Explanation:

If the lights are assumed to be resistance bulbs

Each light has the same current and will each drop one third of the supply voltage.

8 0

3 years ago

Two cars are traveling around identical circular racetracks. Car A travels at a constant speed of 20 m/s. Car B starts at rest a

Tomtit [17]

Answer:

b. it has the same centripetal acceleration as car A.

Explanation:

According to the question, the data provided is as follows

Constant speed of car A = 20 m/s

Constant tangential acceleration until its speed is 40 m/s

Based on the above information, the true statement is the same centripetal acceleration as car A because

As we know that

Centripetal acceleration is

$= \frac{V^2}{r}$

where,

$V^2$ = velocity

r = radius of the path

Now if both car A and car B moving in the same or identical circular path having the same velocity so in this case there is the same centripetal acceleration for that particular time

hence, the second option is correct

3 0

4 years ago

A circular solenoid of radius R = 2cm passes through a square loop of wire with 1 turn and sides of length ℓ = 5cm. The solenoid

ankoles [38]

The answer for this problem is D

4 0

4 years ago

A copper wire is 1.6 m long and its diameter is 1.1 mm. If the wire hangs vertically, how much weight (in N) must be added to it

qaws [65]

Answer:

Weight required = 194.51 N

Explanation:

The elongation is given by

$\Delta L=\frac{PL}{AE}$

Length , L= 1.6 m

Diameter, d = 1.1 mm

Area

$A=\frac{\pi d^2}{4}=\frac{\pi \times (1.1\times 10^{-3})^2}{4}=9.50\times 10^{-7}m^2$

Change in length, ΔL = 2.8 mm = 0.0028 m

Young's modulus of copper, E = 117 GPa = 117 x 10⁹ Pa

Substituting,

$\Delta L=\frac{PL}{AE}\\\\0.0028=\frac{P\times 1.6}{9.50\times 10^{-7}\times 117\times 10^9}\\\\P=194.51N$

Weight required = 194.51 N

8 0

3 years ago