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kodGreya [7K]
4 years ago
8

Two cars are traveling around identical circular racetracks. Car A travels at a constant speed of 20 m/s. Car B starts at rest a

nd speeds up with constant tangential acceleration until its speed is 40 m/s. When car B has the same (tangential) velocity as car A, it is always true that:
a. it has the same linear (tangential) acceleration as car A.
b. it has the same centripetal acceleration as car A.
c. it has traveled farther than car A since starting.
d. it has the same total acceleration as car A.
e. it is passing car A.
Physics
1 answer:
Tomtit [17]4 years ago
3 0

Answer:

b. it has the same centripetal acceleration as car A.

Explanation:

According to the question, the data provided is as follows

Constant speed of car A = 20 m/s

Constant tangential acceleration until its speed is 40 m/s

Based on the above information, the true statement is the same centripetal acceleration as car A because

As we know that

Centripetal acceleration is

= \frac{V^2}{r}

where,

V^2 = velocity

r = radius of the path

Now if both car A and car B moving in the same or identical circular path having the same velocity so in this case there is the same centripetal acceleration for that particular time

hence, the second option is correct

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Answer:

Explanation:

Let a be the acceleration of launch. In 10 seconds , Distance gone up in 10 seconds

s = 1/2at²

= .5 x a x 100

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Velocity after 10 s

u = at = 10a

Now 50a distance in downward direction is travelled in 20 s with initial velocity 10a in upward direction.

s = ut + 1/2 gt²

50a = -10ax20 + .5 x 10x400

250a = 2000

a = 8 m s⁻² .

Velocity after 10 s

= at = 80 m/s

further height reached with this speed under free fall

h = v² / 2g

= 80 x 80 / 2 x 10

= 320 m

height achieved under acceleration

= 50a

= 50 x 8 = 400m

Total height

= 320 + 400= 720 m

velocity after falling from 720 m

v² = 2gh = 2 x10 x 720

v = 120 m/s

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The visible spectrum of the electromagnetic spectrum is made up of which of the following?
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The electric potential in a region of uniform electric field is -1600 V at x = -1.30 m and + 2000 V at x =+ 1.80 m . What is Ex?
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Explanation:

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1. The truck moving to the quarry

let the mass be x

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we know that the kinetic energy is given as

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KE=1/2(x)*20^2

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2. The truck leaving to the quarry

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