Answer:
V = 576 V
Explanation:
Given:
- The area of the two plates A = 0.070 m^2
- The space between the two plates d = 6.3 mm
- Te energy density u = 0.037 J /m^3
Find:
- What must the potential difference between the plates V?
Solution:
- The energy density of the capacitor with capacitance C and potential difference V is given as:
u = 0.5*ε*E^2
- Where the Electric field strength E between capacitor plates is given by:
E = V / d
Hence,
u = 0.5*ε*(V/d)^2
Where, ε = 8.854 * 10^-12
V^2 = 2*u*d^2 / ε
V = d*sqrt ( 2*u / ε )
Plug in values:
V = 0.0063*sqrt ( 2 * 0.037 / (8.854 * 10^-12) )
V = 576 V
It would be option A (a decrease in mass with an increase in volume)
I think th<span>e upward acceleration of the rocket during the burn phase is 7.</span>8 m/s2
0.234m !!!!!! hope this helps :)))
<span>A joule is equal to one watt per second and so we must find out how many seconds are in two hours.
A shortcut you can use is remove the zeros and multiplying the remaining numbers before adding the the zeros back to the total of your result
6 x 6 x 2 = 72 and thus
60 x 60 x 2 = 7200
72 x 15 = 1080 and thus
7200 x 1500 = 10800000 joules
one mega joule equals one million joules
So we can simplify things and say 10.8 MJ</span>
