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kumpel [21]
2 years ago
5

Engineers can determine properties of a structure that is modeled as a damped spring oscillator, such as a bridge, by applying a

driving force to it. A weakly damped spring oscillator of mass
0.246
kg is driven by a sinusoidal force at the oscillator's resonance frequency of
27.8
Hz. Find the value of the spring constant.
The amplitude of the driving force is
0.543
N and the amplitude of the oscillator's steady‑state motion in response to this driving force is
0.877
m. What is the oscillator's damping constant?
Physics
1 answer:
Kazeer [188]2 years ago
8 0

The value of spring constant and the oscillator's damping constant is

K= 6605.667008, b= 0.002884387

Explanation:

For Weakly damping spring oscillator

K/m = W_0^2     (at resonance)

K= mW_0^2

=0.206 * ( 2π * 28.5) ^2

=0.206 * (2π)^2 * (28.5)^2

K= 6605.667008

F = - bV

b= -F/V = -F/ -W_0 * m

=F/W_0 * m

= 0.438N / 2π * 28.5 * 0.848

b= 0.002884387

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The force acting between the particles is

F=k \frac{Q_{1}Q_{2}}{r^2}
Then
Q_{2}= \frac{5.2 \times 10^-^5 \times 0.024^2}{ 9.0 \times 10^9 7.2 \times 10^-^8} =4.622 \times 10^-^1^1C




7 0
2 years ago
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The sum of kinetic energy and potential energy within a system is called
SashulF [63]

Answer:

mechanical energy.

Explanation:

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Explain why an egg thrown at a concrete wall will break, but an egg thrown at a sheet hanging from the ceiling will not. (Be sur
Firlakuza [10]

An egg thrown at a concrete wall will break, but an egg thrown at a sheet hanging from the ceiling will not due to high momentum and acceleration.

<h3>Why an egg thrown at a concrete wall will break?</h3>

An egg thrown at a concrete wall will break, but an egg thrown at a sheet hanging from the ceiling will not because the momentum and acceleration increases when the egg is thrown downward due to gravity but when we throw an egg in the vertical direction, they move against gravity so the momentum and acceleration decreases.

So we can conclude that an egg thrown at a concrete wall will break, but an egg thrown at a sheet hanging from the ceiling will not due to high momentum and acceleration.

Learn more about momentum here: brainly.com/question/7538238

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4 0
2 years ago
The angular velocity (in rpm) of the blade of a blender is given in. If θ=0rad at t=0s, what is the blade's angular position at
Liula [17]

Answer:

θ = 20.9 rad

Explanation:

In a blender after a short period of acceleration the blade is kept at a constant angular velocity, for which we can use the relationship

           w = θ / t

           θ = w t

if we know the value of the angular velocity we can find the angular position, we must remember that all the angles must be in radians

suppose that the angular velocity is w = 10 rpm, let us reduce to the SI system

          w = 10 rpm (\frac{2\pi  rad}{1 rev}) ( \frac{1 min}{60 s} )

= 1,047 rads

let's calculate

          θ = 1,047 20

          θ = 20.9 rad

7 0
3 years ago
If an electric wire is allowed to produce a magnetic field no larger than that of the Earth (0.503 X 104 T) at a distance of 15
dem82 [27]

Answer:

37.725 A

Explanation:

B = magnitude of the magnetic field produced by the electric wire = 0.503 x 10⁻⁴ T

r = distance from the wire where the magnetic field is noted = 15 cm = 0.15 m

i = magnitude of current flowing through the wire = ?

Magnetic field by a long wire is given as

B = \frac{\mu _{o}}{4\pi }\frac{2i}{r}

Inserting the values

0.503\times 10^{-4} = (10^{-7})\frac{2i}{0.15}

i = 37.725 A

6 0
2 years ago
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