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seropon [69]
3 years ago
9

What is the exact volume of the cone?

Mathematics
2 answers:
ipn [44]3 years ago
7 0
C hope that helped have a great time I love it you can do
navik [9.2K]3 years ago
5 0
The correct answer is letter u
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The average rate of change of a function f(x) = x2 between x = 3 and x = 9 is
masya89 [10]

Answer:

12.

Step-by-step explanation:

Average rate of change = (value of the function when x = 9 - value when x=3)

/

(9 - 3)

= f(9) - f(3) / (9-3)

= (9^2 - 3^2) / (9-3)

= 72 / 6

=  12.

6 0
3 years ago
Please help!
erik [133]
For the answer to the question above, 
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3 

<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>

<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>

<span>1 + 9x + 36x^2 + 84x^3 </span>

<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>

<span>(1+x) = 0.98 </span>

<span>x = 0.98 - 1 = -0.02 </span>

<span>Substituting: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>

<span>approximation = 0.834 </span>

<span>Checking the real value in your calculator: </span>

<span>(0.98)^9 = 0.834 </span>

<span>So you have approximated correctly. </span>

<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>

<span> (0.98)^9 = 0.8337477621 </span>

<span>So it is correct to 4</span>
5 0
3 years ago
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If you double just the width of a rectangular prism then you double its volume.
jok3333 [9.3K]
Yes that’s the correct answer
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3 years ago
What is a unit of area with dimensions 1 unit times 1 unit
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1 \text{ u} \cdot 1 \text{ u}=1 \text{ u}^2
5 0
3 years ago
How many real-number solutions does the equation have?
Dmitrij [34]

Answer:

I'm guessing none because the discrimant (sqrt of b squared - 4ac is less than zero, signifying it has no real roots

Step-by-step explanation:

have a happy holidays!

6 0
3 years ago
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