Answer:
y= - 3/4x + 13/2(8.5,0)(0,6.5)
rounded (9,0)(0,7)
Distribute -3 in
-3x + 42 + 6x
3x + 42
Hope this helps!
Answer:
0.2 or 20%
Step-by-step explanation:
If the times of arrival vary uniformly, there is an equal chance of an employee reporting at any given time between 8:40 and 9:30.
The range between 8:40 and 9:30 is 50 minutes.
The range between 9:00 and 9:10 is 10 minutes.
Therefore, the probability that a randomly chosen employee reports to work between 9:00 and 9:10 is:

The probability is 0.2 or 20%.
No because it doesn’t add up to 180°