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AleksAgata [21]
3 years ago
6

Which statements about the values of 4.099 and 40.99 are true? Select all that apply. 4.099 is 110 of 40.99. 4.099 is 1100 of 40

.99. 40.99 is 10 times more than 4.099. 40.99 is 100 times more than 4.099. 4.099 is 10 times more than 40.99.
Mathematics
1 answer:
liraira [26]3 years ago
8 0

Answer:

40.99 is 10 times more than 4.099

Step-by-step explanation:

Given the values :

4.099 and 40.99

4.099 is 110 of 40.99 : 110 * 40.99 = 4508.9 (false)

4.099 is 1100 of 40.99 : 1100 * 40.99 = 45089 (false)

40.99 is 10 times more than 4.099 : (10 * 4.099) = 40.99 (true)

40.99 is 100 times more than 4.099 : (100 * 4.099) = 409.9 ( false)

4.099 is 10 times more than 40.99 : (10 * 40.99) = 409.9 (false)

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The distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26
hjlf

Answer:

Probability that next week's show will have between 30 and 37 million viewers is 0.2248.

Step-by-step explanation:

We are given that the distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26 million with a standard deviation of 8 million.

<em>Let X = number of viewers for the American Idol television show</em>

So, X ~ N(\mu=26,\sigma^{2}=8^{2})

Now, the z score probability distribution is given by;

          Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean = 26 million

            \sigma = standard deviation = 8 million

So, probability that next week's show will have between 30 and 37 million viewers is given by = P(30 < X < 37) = P(X < 37) - P(X \leq 30)

    P(X < 37) = P( \frac{X-\mu}{\sigma} < \frac{37-26}{8} ) = P(Z < 1.38) = 0.91621

    P(X \leq 30) = P( \frac{X-\mu}{\sigma} \leq \frac{30-26}{8} ) = P(Z \leq 0.50) = 0.69146

<em>Therefore, P(30 < X < 37) = 0.91621 - 0.69146 = 0.2248</em>

Hence, probability that next week's show will have between 30 and 37 million viewers is 0.2248.

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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