Here is the graph for my previous question
1 answer:
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*void photo*
Assume M is the Total Money
M/6 + (1/5)(M - M/6) + $600 = M
M/6 + M/5 - M/30 + $ 600 = M
M/6 + M/5 - M/30 - M = -$600
(1/6 + 1/5 - 1/30 - 1)M = -$600
-2M/3 = -$600
2M/3 = $600
M = ($600)(3/2)
M = $900
so the total money is $900
but the money he gave to his children is only 1/3 of the Total Money(M)
therefore,
=(1/3)($900)
=$300
$300 is the total money he gave to his children
Assume M is the Total Money
M/6 + (1/5)(M - M/6) + $600 = M
M/6 + M/5 - M/30 + $ 600 = M
M/6 + M/5 - M/30 - M = -$600
(1/6 + 1/5 - 1/30 - 1)M = -$600
-2M/3 = -$600
2M/3 = $600
M = ($600)(3/2)
M = $900
so the total money is $900
but the money he gave to his children is only 1/3 of the Total Money(M)
therefore,
=(1/3)($900)
=$300
$300 is the total money he gave to his children
Answer:
a) 75
b) 360 students
c) 56 ; 57 ; 58
d) 134 inches
e) 27°
Step-by-step explanation:
a)
b)
c)
d)
e)
Answer: A.$23.00
Step-by-step explanation:
This question is incomplete, please remember to be carful and submit the whole question :)
However, if we assume the money Tommy's class substracted from its penny collection is , we will have the following:
<em>Marty's class collected in a school-wide penny collection contest. If Tommy's class collected,
, then substracted
and then multiplied the difference by 2,they would have the same amount of money as Marty's class. How much money did Tommy's class collect?</em>
<em />
This can be mathematically expressed as follows:
Isolating , which is the amount of money Tommy's class collected:
Hence, the correct option is A.