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Ann [662]
3 years ago
10

Here is the graph for my previous question​

Mathematics
1 answer:
AURORKA [14]3 years ago
3 0

Answer:

COOOOOOL Graph

Step-by-step explanation:

C O O O O O O L  G r a p h

You might be interested in
A coffee stand sells cups of coffee for $6 and cups of tea for $3. Tuesday a total of 75 cups were sold and the total money coll
Lorico [155]

Answer:

46 Teas and 29 Coffees

Step-by-step explanation:

46×3= 138

29×6= 174

174+138=312

4 0
3 years ago
15.5 × [(2 × 2.4) + 3.2] – 24
scZoUnD [109]

Answer:100

Step-by-step explanation:

2 x 2.4=4.8

4.8+3.2=8.0

15.5 x 8.0=124.00

124.00-24=

100

6 0
3 years ago
a guy wire for a tree is 20 ft long, making a 21 angle with the ground. How far is the base of the tree from a stake anchoring t
evablogger [386]

Answer:

18.7 feet far

Step-by-step explanation:

Based on the information given we can conclude that our set up will be a Right triangle (i.e. one angle is 90°), where the hypotenuse will be denoted by the guy wire of 20ft  and angle of 21° is the angle formed between then hypotenuse and the base (i.e. ground).

Thus we want to find the base length (lets call it x ) of this triangle, so we can use trigonometry as we have one angle and the hypotenuse, as follow:

cos(21)=\frac{adjacent side}{hypotenuse}=\frac{baselength}{guywire}\\\\ cos(21)=\frac{x}{20} \\x=20cos(21)\\x=18.671\\x=18.7ft

So the base is approximately 18.7 feet far from the tree of the anchored wire.

8 0
3 years ago
Need the answers plz
Shkiper50 [21]
1)
           x^2 + 4x - 5
y =   --------------------
              3x^2 - 12

Vertcial asym => find the x-values for which the equation is not defined and check whether the limit goes to + or - infinite

=> 3x^2 - 12 = 0 => 3x^2 = 12

=> x^2 = 12 / 3 = 4

=> x = +/-2

Limit of y when x -> 2(+) = ( 2^2 + 4(2) - 5) / 0 = - 1 / 0(+) =  ∞

Limit of y when x -> 2(-) = - 1 / (0(-) = - ∞

Limit of y when x -> - 2(+) = +∞

Limit of y when x -> - 2(-) = -

=> x = 2 and x = - 2 are a vertical asymptotes

Horizontal asymptote => find whether y tends to a constant value when x -> infinite of negative infinite

Limi of y when x -> - ∞ = 1/3

Lim of y when x -> +∞ = 1/3

=> Horizontal asymptote y = 1/3

x - intercept => y = 0

=>
          x^2 + 4x - 5
0 =   ------------------ => x ^2 + 4x  - 5 = 0
              3x^2 - 12

Factor x^2 + 4x - 5 => (x + 5) (x - 1) = 0 => x = - 5 and x = 1

=> x-intercepts x = - 5 and x = 1

Domain: all the real values except x = 2 and x = - 2

2)  y = - 2 / (x - 4) - 1

using the same criteria you get:

Vertical asymptote: x = 4

Horizontal asymptote: y = - 1

Domain:all the real values except x = 4

Range: all the real values except y = - 1

3) 

x/ (x + 2) + 7 / (x - 5) = 14 / (x^2 - 3x - 10)

factor x^2 - 3x - 10 => (x - 5)(x + 2)

Multiply both sides by (x - 5) (x + 2)

=> x(x - 5) + 7( x + 2) = 14

=> x^2 - 5x + 7x + 14 = 14

=> x^2 + 2x = 0

=> x(x + 2) = 0 => x = 0 and x = - 2 but the function is not defined for x = - 2 so it is not a solution => x = 0

Answer: x = 0
4 0
3 years ago
Martin won first place in the 100-meter dash with a time of 14 23/100 seconds.Samuel came in second place with a time of 15 7/10
ohaa [14]

Answer: The answer is 47th of 100 of a second.


Step-by-step explanation:  Given that in the 100-metre dash, Martin won first place by taking a time of

M_t=14\dfrac{23}{100}=\dfrac{1423}{100}~\textup{seconds}.

And, Samuel came second by taking time of

S_t=15\dfrac{7}{10}=\dfrac{157}{10}~\textup{seconds}.

The difference between the time of arrival of Martin and Samuel is given by

t=S_t-M_t=\dfrac{157}{100}-\dfrac{1423}{100}=\dfrac{47}{100}.

Thus, Martin beat Samuel by forty seven - hundredth of a second.



8 0
3 years ago
Read 2 more answers
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