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3 years ago

Can someone help again I’m still in class

Mathematics

2 answers:

AnnZ [28]3 years ago

8 0

Answer:

Step-by-step explanation:

6x3=18

5x3=15

4x3=12

malfutka [58]3 years ago

8 0

The answer 3x.
Explanation
6x3=18
5x3=15
4x3=12

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(2, –2), slope is 1.4

DaniilM [7]

y = 1.4x - 4.8

the equation of a line in ' slope - intercept form ' is

y = mx + c ( m is the slope and c the y- intercept )

the partial equation is y = 1.4x + c

to find c, substitute (2, - 2) into the partial equation

- 2 = 2.8 + c ⇒ c = - 2 - 2.8 = - 4.8

y = 1.4x - 4.8 is the equation in slope- intercept form

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3 years ago

.In the coordinate x,y the point x is calledorigin abscissa line y-axis

Dmitry [639]

Answer:

The x coordinate is known as abscissa (B)

Step-by-step Explanation:

In a Cartesian plane, we learn many such terms which represent a point, or a line, or cooridnates of some points etc $.$

Such terms are:

Origin (Intersection of x axis and y-axis.)
x - axis (Horizontal line)
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abscisaa (x -coordinate)
ordinate (y - coordinate)

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2 years ago

HELP PLZZ I WILL REWARD IF ANSWERS RIGHT

pentagon [3]

I know you have 1 and 3 right but I'm sorry about not knowing the rest.

8 0

3 years ago

Jonas wants to mail a package that weighs 4.2 kilogram. how much dose the package weigh in pounds?

mash [69]

jonas wants to mail a package that weighs 4.2 kilogram. how much dose the package weigh in pounds?

we know that

1 kg = 2.20462262185 lb

1 kg=2.2 lb

we have

4.2 kg

Convert to pounds

4.2 kg=4.2*(2.2)=9.24 pounds

therefore

the answer is 9.24 pounds

7 0

1 year ago

Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr

Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

$A(t) = A(0)e^{-kt}$

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, $A(10) = 0.7278A(0)$ . We use this to find k.

$A(t) = A(0)e^{-kt}$

$0.7278A(0) = A(0)e^{-10k}$

$e^{-10k} = 0.7278$

$\ln{e^{-10k}} = \ln{0.7278}$

$-10k = \ln{0.7278}$

$k = -\frac{\ln{0.7278}}{10}$

$k = 0.03177289938
$

Then

$A(t) = A(0)e^{-0.03177289938t}$

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

$A(5) = A(0)e^{-0.03177289938*5}$

$A(5) = 0.8531$

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0

3 years ago