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rjkz [21]
3 years ago
3

The average annual precipitation in Berkeley, CA is 26.8 inches. Albany, NY has an average precipitation of 39.4 inches. What is

the difference in two cities average annual precipitation.
Equation:


Solution:
Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0

Answer:

The equation is 39.4 - 26.8

The solution is: 12.6 inches.

Step-by-step explanation:

To find the difference in average precipitation between Albany and Berkeley, we subtract the average annual precipitation in each city.

We have that:

Albany: 39.4 inches

Berkeley: 26.8 inches.

So the equation is:

39.4 - 26.8

And the solution is:

39.4 - 26.8 = 12.6 inches.

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8 0
4 years ago
Can't figure it out!!
Zanzabum
\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= \cfrac{1}{x}  \qquad 
\begin{cases}
x_1=2\\
x_2=b
\end{cases}\implies \cfrac{f(b)-f(2)}{b-2}=-\cfrac{1}{10}
\\\\\\
\cfrac{\frac{1}{b}-\frac{1}{2}}{b-2}=-\cfrac{1}{10}\implies 
\cfrac{\frac{2-b}{2b}}{b-2}=-\cfrac{1}{10}\implies \cfrac{2-b}{2b}=-\cfrac{b-2}{10}
\\\\\\


\bf \cfrac{2-b}{2b}=\cfrac{2-b}{10}\implies 20-10b=4b-2b^2\impliedby cross-multiplying
\\\\\\
2b^2-4b-10b+20=0\implies 2b^2-14b+20=0
\\\\\\
b^2-7b+10=0\implies 
(b-2)(b-5)=0\implies b=
\begin{cases}
\boxed{5}\\
2
\end{cases}
8 0
3 years ago
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