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3 years ago

6

If SA=1/2lp+B, find p What is the formula for finding p?

1 answer:

Ilia_Sergeevich [38]3 years ago

8 0

<span>You must get p by itself, so first subtract B from both sides: SA-B=1/2lp. Then multiply both sides by 2, which cancels out the 1/2: 2SA=lp. Then divide both sides by l: (2SA)/l=p.</span>

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2 years ago

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Factor the polynomial 16b^4+30b^3-12b^2

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Answer:

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Step-by-step explanation:

16 $b^{4}$ +30b³-12b²

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It can be also written as :

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2 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

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Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

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So we can say that

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Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

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and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

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it comes

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