Answer:
It is proved that ∆ R S U ≅ ∆ T U S
Step-by-step explanation:
Compare Δ R S U & Δ T U S
∠ R = ∠ T
Side S U is common in both triangle.
So in these two triangles one angle & one side are same, so Property of similarity of triangles is satisfied. so
∆ R S U ≅ ∆ T U S
Proved.
I believe the answer is -2, 7
A is correct, x is less than 2.
Answer:
148°
Step-by-step explanation:
The measure of the intercepted arc QN is twice the measure of inscribed angle QNT.
arc QN = 2(74°) = 148°
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<em>Comment on the question and answer</em>
Your description "on the circle between points Q and N" is ambiguous. You used the same description for both points P and R. The interpretation we used is shown in the attachment. If point P is on the long arc NQ, then the measure of arc QPN will be the difference between 148° and 360°, hence 212°. You need to choose the answer that matches the diagram you have.
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We call angle QNT an "inscribed angle" because it is a degenerate case of an inscribed angle. The usual case has the vertex of the angle separate from the ends of the arc it intercepts. In the case of a tangent meeting a chord, the vertex is coincident with one of the ends of the intercepted arc. The relation between angle measure and arc measure remains the same: 1 : 2.
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