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Svetradugi [14.3K]
3 years ago
13

8/9+ (-5/6) divided by 1/6

Mathematics
1 answer:
Marianna [84]3 years ago
7 0

Answer:

fraction answer: 3/4

decimal answer: 0.75

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The sides of this rectangle are marked off in centimeters. If the rectangle is enlarged proportionally so that the longer side i
Inga [223]

the length of the shorter side is:L  = 13.125cm

<h3>how long will the shorter side be?</h3>

In the longer side we have 8 segments.

We know that the side measures 35 cm, then each one of the 8 segments measures:

35cm/8 = 4.375cm

Now, we can see that in the shorter side we have 3 of these segments.

Then the length of the shorter side is:

L  = 3*(4.375cm) = 13.125cm

If you want to learn more about lengths:

brainly.com/question/2217700

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4 0
2 years ago
PLZZZ ANSWER ASAP!!!
alexgriva [62]

Answer:

(-3,-2)

Step-by-step explanation:

when it is reflected across the y axis then the X coordinate changes to -

6 0
3 years ago
5. Prove the conditional by proving the contrapositive:
Sunny_sXe [5.5K]

Answer + Step-by-step explanation:

<u>the conditional statement</u> :

For two positive integers n and m,

nm = 4 ⇒  (n = 1  or  m = 1)  or  (n=m= 2)

<u>the contrapositive</u>:

(n ≠ 1  and  m ≠ 1)  and  (n ≠ 2 or m ≠ 2) ⇒ nm ≠ 4

<u>Prove the conditional by proving the contrapositive</u> :

Suppose

m ≠ 1

and m ≠ 2

and n ≠ 1

⇒ nm ≠ 1 × n  and  nm ≠ 2 × n  and n ≠ 1

⇒ nm ≠ 4  (because 4 = 4 × 1 or 4 = 2 × 2)

<u>Conclusion</u>:

The contrapositive is true then conditional is true.

3 0
2 years ago
The equation I wrote was F=9/5C+32 Rearrange the equation and solve for C
Trava [24]
F=9/5C+32
rewrite as 9/5C+32=F
9/5C+32-32=F-32
9/5C=F-32
(5*9/5)C=(F-32)*5
9C=5F-160
9/9C=(5F-160)/9
C=(5F-160)/9

4 0
3 years ago
D(-3,5)
asambeis [7]

Answer:

4\sqrt{37} units is the perimeter of square ABCD.

Step-by-step explanation:

Coordinates of square ABCD:

A = (3,4), B = (2,-2), C = (-4-1) , D = (-3,5)

Distance formula: (x_1,y_1),(x_2,y_2)

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance of AB: A = (3,4), B = (2,-2)

AB=\sqrt{(2-3)^2+(-2-4)^2}

AB=\sqrt{(-1)^2+(-6)^2}=\sqrt{37} units

Given that the ABCD is square, then:

AB = BC = CD = DA

Perimeter of the square ABC = AB +BC + CD + DA

AB+ AB+ AB+ AB= 4AB=4\sqrt{37} units

4\sqrt{37} units is the perimeter of square ABCD.

3 0
4 years ago
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