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3 years ago

14

1 answer:

4 0

We can display the information given as an equation:
2000 * $r^{19}$ = 4000; r = increase per annum
Now, we rearrange and solve for r:
$r^{19}$ = 2
r = $\sqrt[19]{2}$ = 1.037.....
We can now work out the increase for 5 years like so:
2000 * $r^{5}$ = 2400.205..... ⇒ $2400

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Help me please!!!!!!!!!!!!!!!!!!!!

Brut [27]

Answer:

if u follow the trend u get 260 and since there's no 260 I'd say the best answer is 240

7 0

3 years ago

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A farmer grows two types of grain in his fields. He has a seed budget of $18,000.00 and has spent $8,100.00 to plant wheat seed

andrew11 [14]

$18,000.00-$8,100.00=$9,900
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5 0

3 years ago

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What is the modulus of 6 + 7i?

lions [1.4K]

$\sqrt{6^2+7^2}=\sqrt{85}$

3 0

3 years ago

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Marita orders 12 yards of material to make banners. If she needs 1 foot of fabric for each banner, how many banners can she make

Alik [6]

Well 3 feet=1 yard
so the conversion factor is 3ft/1yd

so 12 yards converted to feet is
12yd times 3ft/1yd
the yd will cancel and you will be left with 36 feet

each banner is 1 foot so 36/1=36
she can make 36 banners

7 0

3 years ago

The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

likoan [24]

Answer:

A) 3%

B) Product A

Step-by-step explanation:

Exponential Function

General form of an exponential function: $y=ab^x$

where:

a is the initial value (y-intercept)
b is the base (growth/decay factor) in decimal form
x is the independent variable
y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

Part A

Product A

Assuming the function for Product A is exponential:

$f(x) = 0.69(1.03)^x$

The base (b) is 1.03. As b > 1 then it is an increasing function.

To calculate the percentage increase/decrease, subtract 1 from the base:

⇒ 1.03 - 1 = 0.03 = 3%

Therefore, product A is increasing by 3% each year.

Part B

$\sf percentage\:change=\dfrac{final\:value-initial\:value}{initial\:value} \times 100$

To calculate the percentage change in Product B, use the percentage change formula with two consecutive values of f(t) from the given table:

$\implies \sf percentage\:change=\dfrac{10201-10100}{10100}\times 100=1\%$

Check using different two consecutive values of f(t):

$\implies \sf percentage\:change=\dfrac{10303.01-10201}{10201}\times 100=1\%$

Therefore, as 3% > 1%, Product A recorded a greater percentage change in price over the previous year.

Although the question has not asked, we can use the given information to easily create an exponential function for Product B.

Given:

a = 10,100
b = 1.01
n = t - 1 (as the initial value is for t = 1 not t = 0)

$\implies f(t) = 10100(1.01)^{t-1}$

To check this, substitute the values of t for 1 through 4 into the found function:

$\implies f(1) = 10100(1.01)^{1-1}=10100$

$\implies f(2) = 10100(1.01)^{2-1}=10201$

$\implies f(3) = 10100(1.01)^{3-1}=10303.01$

$\implies f(4) = 10100(1.01)^{4-1}=10406.04$

As these values match the values in the given table, this confirms that the found function for Product B is correct and that Product B increases by 1% per year.

4 0

2 years ago