All categories

3 years ago

What is the momentum of an object in splace

Physics

1 answer:

forsale [732]3 years ago

5 0

Answer:

The total momentum of the universe is always the same and is equal to zero. The total momentum of an isolated system never changes. Momentum can be transferred from one body to another.

Momentum quantifies how likely an object is to stay in motion. Momentum can also be explained using the equation, p=mv, where p is equal to momentum, m is equal to mass, and v is equal to velocity.

Explanation:

You might be interested in

A car travels 50 kilometers in 30 minutes. Which<br> about the motion of the car are true?

irga5000 [103]

Answer:

1500

Explanation:

is that all the question?

6 0

1 year ago

A tuning fork labeled 392 Hz has the tip of each of its two prongsvibrating with an amplitude of 0.600mma) What is the maximum s

DanielleElmas [232]

a) 1.48 m/s

The tuning fork is moving by simple harmonic motion: so, the maximum speed of the tip of the prong is related to the frequency and the amplitude by

$v_{max}=\omega A$

where

$v_{max}$ is the maximum speed

$\omega$ is the angular frequency

A is the amplitude

For the tuning fork in the problem, we have

$\omega=2\pi f=2 \pi(392 Hz)=2462 rad/s$ , where f is the frequency

$A=0.600 mm=6\cdot 10^{-4} m$ is the amplitude

Therefore, the maximum speed is

$v_{max}=(2462 rad/s)(6\cdot 10^{-4}m)=1.48 m/s$

b) $3.0\cdot 10^{-5} J$

The fly's maximum kinetic energy is given by

$K=\frac{1}{2}mv_{max}^2$

where

$m=0.0270 g=2.7\cdot 10^{-5} kg$ is the mass of the fly

$v_{max}=1.48 m/s$ is the maximum speed

Substituting into the equation, we find

$K=\frac{1}{2}(2.7\cdot 10^{-5}kg)(1.48 m/s)^2=3.0\cdot 10^{-5} J$

7 0

2 years ago

A 40.0 -kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 13

Irina18 [472]

The work done by the gravitational force = 0

Given the mass of the box = 40 kg

The box is initially at rest.

Distance moved by the applied force = 5m

Force applied = 130 N

Co-efficient of friction between the box and floor = 0.3

The box is moved only in the horizontal direction by the applied force.

Gravitational force is applied in a direction perpendicular to the applied force. hence it doesn't do any work on the box.

Therefore, the work done by the gravitational force is zero.

Learn more about the gravitational force at brainly.com/question/862529

#SPJ4

3 0

1 year ago

What determines the velocity of an object?

BARSIC [14]

I think it’s A not 100% sure

4 0

2 years ago

A 75.0kg bicyclist (including the bicycle) is pedaling to the right, causing her speed to increase at a rate of 2.20m/s^2, despi

malfutka [58]

1) 4 forces

2) 165 N

3) 225 N

Explanation:

There are in total 4 forces acting on the bicylist:

- The gravitational force on the byciclist, acting vertically downward, of magnitude $mg$ , where m is the mass of the bicyclist and g is the acceleration due to gravity

- The normal force exerted by the floor on the bicyclist and the bike, N, vertically upward, and of same magnitude as the gravitational force

- The force of push F, acting horizontally forward, given by the push exerted by the bicylist on the pedals

- The air drag, R, of magnitude R = 60.0 N, acting horizontally backward, in the direction opposite to the motion of the bicyclist

The magnitude of the net force on the bicyclist can be calculated by considering separately the two directions.

- Along the vertical direction, we have the gravitational force (downward) and the normal force (upward); these two forces are equal in magnitude, since the acceleration of the bicyclist along this direction is zero, therefore the net force in this direction is zero.

- Along the horizontal direction, the two forces (forward force of push and air drag) are balanced, since the acceleration is non-zero, so we can use Newton's second law of motion to find the net force on the bicylist:

$F_{net}=ma$