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VLD [36.1K]
3 years ago
9

What is the momentum of an object in splace

Physics
1 answer:
forsale [732]3 years ago
5 0

Answer:

The total momentum of the universe is always the same and is equal to zero. The total momentum of an isolated system never changes. Momentum can be transferred from one body to another.

Momentum quantifies how likely an object is to stay in motion. Momentum can also be explained using the equation, p=mv, where p is equal to momentum, m is equal to mass, and v is equal to velocity.

Explanation:

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Question 7 (3 points)
vagabundo [1.1K]

Answer:

how you can convert electrical energy to mechanical energy

Explanation:

In the Electric Motor lab, what did you attempt to demonstrate with the electric motor?

In the Electric Motor lab, the experiment usually demonstrate energy conversion process, from electrical energy to mechanical energy. This mechanical energy can also be converted back to electrical energy using a generator.

Therefore, what you attempted to demonstrate with the electric motor, is how you can convert electrical energy to mechanical energy

5 0
4 years ago
What is the medium when you are in your bedroom listening to the radio?
GrogVix [38]

Answer:

this equation doesn't work

Explanation:

no one listens to radio anymore

8 0
3 years ago
Read 2 more answers
an object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m. determine the image height (in cm)
Juli2301 [7.4K]

Given :

An object 50 cm high is placed 1 m in front of a converging lens whose focal length is 1.5 m.

To Find :

the image height (in cm).

Solution :

By lens formula :

\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}

Here, u = - 100 cm

f =  150 cm

\dfrac{1}{v} - \dfrac{1}{-100} = \dfrac{1}{150}\\\\v = - 300 \ cm

Now, magnification is given by :

m = \dfrac{v}{u} = \dfrac{h_i}{h_o}\\\\h_i = \dfrac{300}{100}\times 1\\\\h_i = 3 \ m

Therefore, the image height is 3 m or 300 cm.

5 0
3 years ago
A jumbo jet of mass 100,000 kg during takeoff experience a thrust for each of its four engines of 50,000 N. producing an acceler
PtichkaEL [24]

Answer:

F=MA

5OOOO=100000×A

50000/100000=A

A=5/10 M/ S SQ

A=0.5 M/S SQ.

8 0
4 years ago
Outside controlled airspace, the minimum flight visibility requirement for vfr flight above 1,200 feet agl and below 10,000 feet
nalin [4]
The least possible flight visibility prerequisite for VFR flight above 1200 feet AFL and below 10000 feet MSL for the duration of daylight hours is 1 mile in the external controlled airspace. In aeronautics, visual meteorological conditions or as called as VMC is an aviation flight group in which visual flight rules or VFR is allowed that is in circumstance in which pilot have adequate visibility to fly the aircraft sustaining visual leave-taking from terrain and other aircraft. They are the contradictory of instrument meteorological conditions. The border standards among instrument meteorological conditions and visual meteorological circumstances are recognized as the visual meteorological conditions minima and are well-defined by visibility, cloud ceilings for take offs and landing and cloud allowances.  
3 0
3 years ago
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