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aivan3 [116]
3 years ago
15

Calculate the minimum frequency of ultrasound (in Hz) that will allow you to see details as small as 0.193 mm in human tissue. (

Assume the speed of sound through human tissue is 1540 m/s.) What is the effective depth to which this sound is effective as a diagnostic probe?
Physics
1 answer:
STatiana [176]3 years ago
8 0

Answer:

f = 7.97 x 10⁶ Hz = 7.97 MHz

Explanation:

The speed of a wave is given by the following formula:

v = f\lambda

where,

v = speed of the ultrasound wave through human tissue = 1540 m/s

f = frequency of ultrasound wave required = ?

λ = wavelength of ultrasound waves = smallest detail required = 0.193 mm

λ = 0.193 mm = 1.93 x 10⁻⁴ m

Therefore,

1540\ m/s = f(1.93\ x\ 10^{-4}\ m)\\f = \frac{1540\ m/s}{1.93\ x\ 10^{-4}\ m}

<u>f = 7.97 x 10⁶ Hz = 7.97 MHz</u>

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