To solve this problem, we must know the gravitational force
of the planet. The equation would be,

This would calculate the force between two objects with
masses m1 and m2 and the gravitational constant, G, is 6.67 x 10^-11 m3 s-2
kg-1 and with r as the distance between the objects.
Thus,
F = (6.67 x 10^-11 m3 s-2 kg-1) * (5.68 x 10^26 kg) * (65
kg) * ((1/6.03 x 10^7 m)^2)
F = 678 kg/s^2 or 678 N
Answer is letter B.
Here are the answers to the given question above.
<span>Relative dating uses laws or principles of stratigraphy and paleontology. These laws of relative dating are:
-</span><span>law of original horizontality
-</span><span>law of superposition
-</span><span>law of original lateral continuity
-</span><span>law of cross-cutting or intrusive relationships
Hope these are the answers that you are looking for.</span>
You would probably have a low frequency due to how much the wavelength is spread out.
Answer:
171.5 N
Explanation:
The gravitational force on an object due to the Earth is given by

where
m is the mass of the object
g is the acceleration due to gravity
The acceleration due to gravity at a certain height h above the Earth is given by

where:
G is the gravitational constant
is the Earth's mass
is the Earth's radius
Here,

So the acceleration due to gravity is

We know that the mass of the object is
m = 70 kg
So, the gravitational force on it is

No,because they may have more particles