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m_a_m_a [10]
3 years ago
13

PLEASE ANSWER it is question 3 not 2 but it is in the picture.

Mathematics
1 answer:
AlekseyPX3 years ago
8 0

Step-by-step explanation:

\frac{ {3}^{a}  \times  \sqrt{6} }{9 \times  \sqrt{54} }  = 1 \\  {3}^{a}  \sqrt{6}  = 9 \sqrt{54}  \\  {3}^{a}  =  \frac{9 \sqrt{54} }{ \sqrt{6} }  \\  {3}^{a}  = 27 \\ a = 3

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3 years ago
Factor –7x3 + 21x2 + 3x – 9 by grouping. What is the resulting expression?
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4 0
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A ladder leans against a wall 6 ft above the ground. The base of the ladder is 3 ft from the wall. How long is the ladder?
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6.71

Step-by-step explanation:

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7 0
3 years ago
Social studies class is 4 more than two times the length of recess, in minutes.
makvit [3.9K]
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8 0
3 years ago
PLSS HELP ILL GIVE YOU BRAINLIEST!!
uysha [10]

Answer:

Step-by-step explanation:

Q1)

Use Phythogoras theorem:

(AC)^2=(BC)^2+(AB)^2\\BC^2=AC^2-AB^2\\BC^2=6^2-4^2\\BC^2=36-16\\BC^2=20\\\\Apply\ square\ on\ both\ sides\\\\\sqrt{BC^2}=\sqrt{20}  \\BC=\sqrt{20} \\BC=\sqrt{10(2)} \\BC=\sqrt{5(2)(2)} \\BC=2\sqrt{5}

Q2)

Apply phythogoras theorem:

CD^2=CE^2+DE^2\\CD^2=7^2+9^2\\CD^2=49+81\\CD^2=130\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{CD^2} = \sqrt{130} \\\\CD=\sqrt{130} \\\\CD=11.4

Q3)

Apply phythogoras theorem again:

BC^2=BD^2+CD^2\\BC^2=7^2+13^2\\BC^2=49+169\\BC^2=218\\\\Apply\ square\ root\ on\ both\ sides\\\\\\sqrt{BC^2} =\sqrt{218}  \\\\BC=\sqrt{218} \\\\BC=14.76

I have an attached an image for Question 2 for better understanding the length of DE in question equals 15 - 6 = 9

4 0
3 years ago
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