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m_a_m_a [10]
3 years ago
13

PLEASE ANSWER it is question 3 not 2 but it is in the picture.

Mathematics
1 answer:
AlekseyPX3 years ago
8 0

Step-by-step explanation:

\frac{ {3}^{a}  \times  \sqrt{6} }{9 \times  \sqrt{54} }  = 1 \\  {3}^{a}  \sqrt{6}  = 9 \sqrt{54}  \\  {3}^{a}  =  \frac{9 \sqrt{54} }{ \sqrt{6} }  \\  {3}^{a}  = 27 \\ a = 3

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Say that australia has a working population of 11,565,470 people, and that the average salary is $26,450 annually. how much tax
Anna [14]

Answer:$96,054,697,990 ”C”

Step-by-step explanation: Calculating the amount taxed from each person in the working population:31.4% × 26450 = $8305.30 per personThe amount of tax collected from the whole population:8305.30 × 11565470 = $96,054,697,990 ⇒ This is the annual tax revenue

6 0
2 years ago
Benjamin and his sister shared a large sandwich. Benjamin ate 3/5 of the sandwich and his sister ate 1/7 of the sandwich.
astraxan [27]

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Benjamin ate 16/35 more than how much his sister ate of the sandwich.

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4 years ago
Can anyone help me with calculus??
gogolik [260]

1. If f(x)=(x+1)^4, then f'(x)=4(x+1)^3. So f'(1)=32.

2. With x^2+y^2=1, we differentiate once with respect to x and get

\dfrac{\mathrm d}{\mathrm dx}[x^2+y^2]=\dfrac{\mathrm d}{\mathrm dx}1

2x+2y\dfrac{\mathrm dy}{\mathrm dx}=0

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac xy

Differentiate again with respect to x and we get

\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{y-x\frac{\mathrm dy}{\mathrm dx}}{y^2}

\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{y+\frac{x^2}y}{y^2}=-\dfrac{y^2+x^2}{y^3}=-\dfrac1{y^3}

(where y\neq0).

3. Check the one-side limits where the pieces are split. For f to be continuous everywhere, we need

\displaystyle\lim_{x\to-1^-}f(x)=\lim_{x\to-1^+}f(x)=f(-1)

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)

In the first case, we have

\displaystyle\lim_{x\to-1^-}f(x)=\lim_{x\to-1}x+2=1

\displaystyle\lim_{x\to-1^+}f(x)=\lim_{x\to-1}x^2=1

and f(-1)=1, so it's continuous here.

In the second case, we have

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1}x^2=1

\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1}3-x=2

so f is discontinuous at x=1.

4. If f(x)=3xe^x, then f'(x)=3e^x+3xe^x=3e^x(1+x)[tex]. So [tex]f'(0)=3.

5. If f(x)=(x+1)^2(x+2)^3, then f'(x)=2(x+1)(x+2)^3+3(x+1)^2(x+2)^2=(x+1)(x+2)^2(5x+7). So f'(0)=28.

6. The average velocity over [1, 2] is given by

\dfrac{s(2)-s(1)}{2-1}=(2^2+2)-(1^2+1)=4

7. If f(x)=\sin^2x, then f'(x)=2\sin x\cos x=\sin2x. So f'\left(\dfrac\pi4\right)=\sin\dfrac\pi2=1.

8. If f(x)=\log_23x, then

2^{f(x)}=3x\implies e^{\ln2^{f(x)}}=3x\implies e^{(\ln2)f(x)}=3x

Differentiating, we get

(\ln2)f'(x)e^{(\ln2)f(x)}=(\ln2)3xf'(x)=3\implies f'(x)=\dfrac1{(\ln2)x}

So f'(1)=\dfrac1{\ln2}.

9. If f(x)=\dfrac1{x^2}, then f'(x)=-\dfrac2{x^3}. So f'(1)=-2

10. If f(x)=-\dfrac{6x}{e^x+1}, then f'(x)=-\dfrac{6(e^x+1)-6xe^x}{(e^x+1)^2}=-\dfrac{6e^x(1-x)+6}{(e^x+1)^2}. So f'(0)=-\dfrac{12}4=-3.

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4 years ago
What is DA equal to? Brainiest if correct and please show your answer.
Naddik [55]

Answer:

<h2>DA is equal to <u>25</u> or BA</h2>

Step-by-step explanation:

ABC

ADC

  1. Since we know that line CA is equal to line CA because of <em>reflexive property</em>
  2. Angle BAC and DAC are equal because of <em>definition of an angle bisector</em>
  3. Angle ABC and ADC are equal because of <em>definition of an angle bisector</em>
  4. This will give us <em>ASA</em>, proving to us that all sides and angles are congruent <u>(this was already given to us)</u>
  5. So, if BA is 25, and we know that BA is congruent to DA, this tells us that DA is 25

5 0
1 year ago
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