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saul85 [17]
3 years ago
10

Which equation matches the function shown in the graph?

Mathematics
2 answers:
Tpy6a [65]3 years ago
8 0
The answer should be D
salantis [7]3 years ago
5 0

Answer:

the answer is A. y=2sin(1/2x)+1

Step-by-step explanation:

I input all four functions on desmos (a graphing calculator), and saw that A. y=2sin(1/2x)+1 was similar to the function shown in the graph

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What is larger multiple of 6
nalin [4]

Answer:

96

Step-by-step explanation:

Here again are the multiples of 6, 0, 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96,… If we divide any of these multiples by 6, we get a quotient with remainder zero.

6 0
3 years ago
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A kite has a string that is 300 ft long, The flying kite forms a 62°angle with a
anygoal [31]

Answer:

270.9 ft

Step-by-step explanation:

6 + 300sin(62)

= 270.8842779 ft

8 0
4 years ago
Use the remainder theorem to divide 5x^2+9x-2 by x+3. What is the remainder
marishachu [46]

Answer:

16

Step-by-step explanation:

Given

f(x)=5x^2+9x-2

Remainder theorem states that when f(x) is divided by x-a then the remainder can be calculated by calculating f(a).

Now Using the remainder theorem to divide 5x^2+9x-2 by x+3 to find the remainder:

f(x)=5x^2+9x-2

f(-3) = 5(-3)^2 +9(-3) -2

       =5(9) - 27 -2

       = 45-29

        = 16 !

7 0
3 years ago
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Could you explain why the answer 125 was supposed to be negative while my answer 81 was correct?
hichkok12 [17]

Answer:

Step-by-step explanation:

Realize what (-5)^3 means

(-5)(-5)(-5)

25(-5)

-125

meanwhile

(-9)^2 is

(-9)(-9)

81

Basically a negative times a negative is always positive, but when a negative number is cubed (or raised to any odd exponent for that matter) the product will be negative.

5 0
3 years ago
To find the interquartile range you need to ____the upper and lower quartile values.​
Blababa [14]

Answer:

The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median

8 0
3 years ago
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