Angle 3 and angle 4 are supplementary angles and when added together need to equal 180 degrees.
To find angle 4 subtract angle 3 from 180.
Angle 4 = 180 - 101 = 79 degrees.
M∠ADB + m∠BDC = m∠ADC [<span>angle addition postulate]
x + x + 10 = 60
2x + 10 = 60
2x = 60 - 10
2x = 50
x = 50/2
x = 25
a
m</span>∠ADB = x = 25°
b
m∠BDC = x + 10 = 25 + 10 = 35°
89 is prime 16 is composite 17 is prime 25 is composite
Please consider the attached file.
We can see that triangle JKM is a right triangle, with right angle at M. Segment KM is 6 units and segment MJ is 3 units. We can also see that KJ is hypotenuse of right triangle.
We will use Pythagoras theorem to solve for KJ as:
Now we will take positive square root on both sides:
Therefore, the length of line segment KJ is 
and option D is the correct choice.
Let x = 1. Substitute x = 1 into the equation:
y = -9X(1)+3
y = -9+3
y = -6
-> Ordered pairs are written in the form (x,y). Thus in this case, your ordered pair is (1,-6).
