X^4+ 3x^3+4x^2-8 | x+2 = x^3+x^2+2x-4
-x^4-2x^3
-----------------------
x^3+4x^2-8
-x^3-2x^2
-------------------------
2x^2-8
-2x^2-4x
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-4x-8
4x+8
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is a factor because (x+2)(x^3+x^2+2x-4)=x^4+3x^3+4x^2-8
Answer:
(6,-2)
Step-by-step explanation:
graph and see the point where they cross and that is the solution
Taking the square root of both sides of the equation. on e2020
Answer:
the answer would be F
Step-by-step explanation:
Answer:the binomial that is not a factor is x - 4
Step-by-step explanation:
The given polynomial is expressed as
P(x) = 3x^3 + 5x^2 - 4x - 4
The first step is to equate the polynomial to zero. It becomes
P(x) = 3x^3 + 5x^2 - 4x - 4 = 0
We would substitute each value of x into the polynomial. If the result is zero, then it is a factor.
1) x - 4 = 0, x = 4
Therefore,
3×4^3 + 5 × 4^2 - 4 × 4 - 4 = 0
384 + 80 - 16 - 4 = 444
2) x + 2 = 0, x = - 2
Therefore,
3 × -2^3 + 5 × -2^2 - 4 × -2 - 4 = 0
- 24 + 20 + 8 - 4 = 0
3) x = 1
Therefore,
3 × 1^3 + 5 × 1^2 - 4 × 1 - 4 = 0
4) 3x + 2 = 0
3x = - 2
x = - 2/3
Therefore
3 × (-2/3)^3 + 5 × (-2/3)^2 - 4 × (-2/3) - 4 = 0
