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3 years ago

I WILL MARK BRAINLIST, PLEASE HELP!

Mathematics

1 answer:

Nastasia [14]3 years ago

4 0

Answer:

Step-by-step explanation:

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You drive 230 miles on 8 gallons of gas at this rate how many miles will you get from 10 gallons??

Evgesh-ka [11]

Answer: 287.5

Step-by-step explanation: because 8 devided by 230 is 28.75 and 28.75 times 10 is 287.5

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3 years ago

tell how you know that a system of two linear equations has more than one solution. how many solutions will such a system have?

riadik2000 [5.3K]

For a <span>system of two linear equations to have more than one solution, the lines representing the equations must coincide, i.e. must be the same or a multiple of each other. In that case, the system will have infinitely many solutions.
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3 years ago

Write 56/90 as a decimal.

gizmo_the_mogwai [7]

56/90

" / " means divide

56 divided by 90 = 0.62 with a line over the 2 because it is repeating

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3 years ago

Read 2 more answers

POINTS IF HELP!!! Please help me?

Lilit [14]

2.24 should be correct

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3 years ago

Read 2 more answers

Bt= 8500 *(8/27)^t/3After a special medicine is introduced into a Petri dish full of bacteria, the number of bacteria remaining

ozzi

Answer:

Every 1.71 seconds, the bacteria loses $\frac{1}{2}$

Step-by-step explanation:

Given

$B(t) = 8500 * (\frac{8}{27})^\frac{t}{3}\\$

Required [Missing from the question]

Every __ seconds, the bacteria loses $\frac{1}{2}$

First, we model the function from t/3 to t.

$B(t) = 8500 * (\frac{8}{27})^\frac{t}{3}\\$

Apply law of indices

$B(t) = 8500 * (\frac{8^\frac{1}{3}}{27^\frac{1}{3}})^t$

Evaluate each exponent

$B(t) = 8500 * (\frac{2}{3})^t$ --- This gives the number of bacteria at time t

At time 0, we have:

$B(0) = 8500 * (\frac{2}{3})^0$

$B(0) = 8500 * 1$

$B(0) = 8500$

Let r be the time 1/2 disappears.

When 1/2 disappears, we have:

$B(r) = \frac{B(0)}{2}$

$B(r) = \frac{8500}{2}$

$B(r) = 4250$

So, we have:

$B(t) = 8500 * (\frac{2}{3})^t$

Substitute r for t

$B(r) = 8500 * (\frac{2}{3})^r$

Substitute $B(r) = 4250$

$4250 = 8500 * (\frac{2}{3})^r$

Divide both sides by 8500

$\frac{4250}{8500} = (\frac{2}{3})^r$

$\frac{1}{2} = (\frac{2}{3})^r$

Take log of both sides

$log(\frac{1}{2}) = log (\frac{2}{3})^r$

Apply law of logarithm

$log(\frac{1}{2}) = r\ log (\frac{2}{3})$

Make r the subject

$r = log(\frac{1}{2}) / log (\frac{2}{3})$

$r = \frac{-0.3010}{-0.1761}$

$r = 1.71$

<em>Hence, it reduces by 1/2 after every 1.71 seconds</em>

6 0

3 years ago