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Alex Ar [27]
3 years ago
8

Do you want to talk?

Computers and Technology
1 answer:
Novay_Z [31]3 years ago
4 0

Answer: yeah

Explanation: lonely

You might be interested in
Stephen needs to insert a field into a building block that will contain variable data. Which keyboard shortcut can he use to tog
STatiana [176]

Answer:

Alt + F9

Explanation:

The Keyboard shortcut that Stephen can use use to toggle between data and the field codes is Alt + F9. This is in regards to Microsoft Word Fields for both Windows and Mac operating systems. Although ALT + F9 will toggle between these two but for all the fields within the document. If you want to toggle between a single or various fields it would be Shift + F9.

8 0
3 years ago
Write a program that can be used to assign seats for a commercial airplane. The airplane has 13 rows, with six seats in each row
d1i1m1o1n [39]

Answer:

See explaination

Explanation:

#include <iostream>

#include <string>

#include <stdio.h>

#include <cst dlib>

using namespace st d;

int main(int argc, char *argv[])

{

int airplane[13][6];

char airchar[13][6];

string ticket;

int row[2];

char seat;

//--------------------------------------------

for(int i = 0; i < 13; i++)

{

for(int j = 0; j < 6; j++)

{

airchar[i][j] = '*';

airplane[i][j] = 0;

}

}

//--------------------------------------------

for(;;)

{

cout<<"Rows 1 and 2 are first class (F C)"<<endl;

cout<<"Rows 3 through 7 are business class (B C)"<<endl;

cout<<"Rows 8 through 13 are economy class (E C)"<<endl;

cout<<endl;

cout<<"* - Available"<<endl;

cout<<"X - Occupied"<<endl;

cout<<endl;

cout<<" \t A\t B\t C\t D\t E\t F"<<endl;

cout<<"Row 1\t"<<airchar[0][0]<<"\t"<<airchar[0][1]<<"\t"

<<airchar[0][2]<<"\t"<<airchar[0][3]<<"\t"<<airchar[0][4]<<"\t"

<<airchar[0][5]<<endl;

cout<<"Row 2\t"<<airchar[1][0]<<"\t"<<airchar[1][1]<<"\t"

<<airchar[1][2]<<"\t"<<airchar[1][3]<<"\t"<<airchar[1][4]<<"\t"

<<airchar[1][5]<<endl;

cout<<"Row 3\t"<<airchar[2][0]<<"\t"<<airchar[2][1]<<"\t"

<<airchar[2][2]<<"\t"<<airchar[2][3]<<"\t"<<airchar[2][4]<<"\t"

<<airchar[2][5]<<endl;

cout<<"Row 4\t"<<airchar[3][0]<<"\t"<<airchar[3][1]<<"\t"

<<airchar[3][2]<<"\t"<<airchar[3][3]<<"\t"<<airchar[3][4]<<"\t"

<<airchar[3][5]<<endl;

cout<<"Row 5\t"<<airchar[4][0]<<"\t"<<airchar[4][1]<<"\t"

<<airchar[4][2]<<"\t"<<airchar[4][3]<<"\t"<<airchar[4][4]<<"\t"

<<airchar[4][5]<<endl;

cout<<"Row 6\t"<<airchar[5][0]<<"\t"<<airchar[5][1]<<"\t"

<<airchar[5][2]<<"\t"<<airchar[5][3]<<"\t"<<airchar[5][4]<<"\t"

<<airchar[5][5]<<endl;

cout<<"Row 7\t"<<airchar[6][0]<<"\t"<<airchar[6][1]<<"\t"

<<airchar[6][2]<<"\t"<<airchar[6][3]<<"\t"<<airchar[6][4]<<"\t"

<<airchar[6][5]<<endl;

cout<<"Row 8\t"<<airchar[7][0]<<"\t"<<airchar[7][1]<<"\t"

<<airchar[7][2]<<"\t"<<airchar[7][3]<<"\t"<<airchar[7][4]<<"\t"

<<airchar[7][5]<<endl;

cout<<"Row 9\t"<<airchar[8][0]<<"\t"<<airchar[8][1]<<"\t"

<<airchar[8][2]<<"\t"<<airchar[8][3]<<"\t"<<airchar[8][4]<<"\t"

<<airchar[8][5]<<endl;

cout<<"Row 10\t"<<airchar[9][0]<<"\t"<<airchar[9][1]<<"\t"

<<airchar[9][2]<<"\t"<<airchar[9][3]<<"\t"<<airchar[9][4]<<"\t"

<<airchar[9][5]<<endl;

cout<<"Row 11\t"<<airchar[10][0]<<"\t"<<airchar[10][1]<<"\t"

<<airchar[10][2]<<"\t"<<airchar[10][3]<<"\t"<<airchar[10][4]<<"\t"

<<airchar[10][5]<<endl;

cout<<"Row 12\t"<<airchar[11][0]<<"\t"<<airchar[11][1]<<"\t"

<<airchar[11][2]<<"\t"<<airchar[11][3]<<"\t"<<airchar[11][4]<<"\t"

<<airchar[11][5]<<endl;

cout<<"Row 13\t"<<airchar[12][0]<<"\t"<<airchar[12][1]<<"\t"

<<airchar[12][2]<<"\t"<<airchar[12][3]<<"\t"<<airchar[12][4]<<"\t"

<<airchar[12][5]<<endl;

cout<<endl;

cout<<"Enter Ticket type (F C, B C, or E C): ";

cin>>ticket;

cout<<"Desired Row: ";

cin>>row[0];

cout<<"Desired seat (A,B,C,D,E or F): ";

cin>>seat;

switch(seat)

{

case 'A':

case 'a':

row[0] = row[0] - 1;

row[1] = 1;

row[1] = row[1] - 1;

break;

case 'B':

case 'b':

row[0] = row[0] - 1;

row[1] = 2;

row[1] = row[1] - 1;

break;

case 'C':

case 'c':

row[0] = row[0] - 1;

row[1] = 3;

row[1] = row[1] - 1;

break;

case 'D':

case 'd':

row[0] = row[0] - 1;

row[1] = 4;

row[1] = row[1] - 1;

break;

case 'E':

case 'e':

row[0] = row[0] - 1;

row[1] = 5;

row[1] = row[1] - 1;

break;

case 'F':

case 'f':

row[0] = row[0] - 1;

row[1] = 6;

row[1] = row[1] - 1;

break;

}

if(ticket == "F C")

{

if(row[0]+1 == 1 || row[0]+1 == 2)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

else if(ticket == "B C")

{

if(row[0]+1 == 3 || row[0]+1 == 4 || row[0]+1 == 5

|| row[0]+1 == 6|| row[0]+1 == 7)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

else if(ticket == "E C")

{

if(row[0]+1 == 8 || row[0]+1 == 9 || row[0]+1 == 10

|| row[0]+1 == 11|| row[0]+1 == 12|| row[0]+1 == 13)

{

if(airplane[row[0]][row[1]] == 0)

{

airplane[row[0]][row[1]] = 1;

airchar[row[0]][row[1]] = 'X';

}

else if(airplane[row[0]][row[1]] == 1)

{

cout<<"Message: Seat "<<row[0] + 1<<seat<<" is already occupied"<<endl;

system("Pause");

}

}

else

{

cout<<"Wrong Class"<<endl;

system("Pause");

system("cls");

continue;

}

}

row[0] = 0;

row[1] = 0;

system("cls");

}

return 0;

}

6 0
4 years ago
75,15,25,5,15 what's next
Fittoniya [83]

Answer:

3

Explanation:

The sequence seems to follow a 2-step pattern.

1)Divide the first number by 5 to get the second number.

2)Add 10 to the second number to get the third number.

75/5 = 15

15 + 10 = 25

25/5 = 5

5 + 10 = 15

---> 15/5 = [3] (Answer)

3 0
3 years ago
If you attempt an edgeunity quiz is your latest attempt the one counted?
tekilochka [14]

Answer:

Hello

Explanation:

Hello profile picture of a nub how are you doing today?

8 0
3 years ago
A Transmission Control Protocol (TCP) connection is established and two devices ensure that they're speaking the same protocol.
son4ous [18]

Answer:

The answer is "Three-way handshake".

Explanation:

In this mechanism, two processes associated with communication throughout SEO techniques. In this, the sequence of data packets and recognized by the number of exchanges during the threefold handshake process.

  • This method initiating the process between two apps,  Handshaking begins whenever a computer sends the message to its system.
  • The process of the communication system has been established into the two devices,  which simply send many messages, which allow them to settle the protocol for communication.
6 0
3 years ago
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