Answer: 12 students
Step-by-step explanation:
Let X and Y stand for the number of students in each respective class.
We know:
X/Y = 2/5, and
Y = X+24
We want to find the number of students, x, that when transferred from Y to X, will make the classes equal in size. We can express this as:
(Y-x)/(X+x) = 1
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We can rearrange X/Y = 2/5 to:
X = 2Y/5
The use this value of X in the second equation:
Y = X+24
Y =2Y/5+24
5Y = 2Y + 120
3Y = 120
Y = 40
Since Y = X+24
40 = X + 24
X = 16
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Now we want x, the number of students transferring from Class Y to Class X, to be a value such that X = Y:
(Y-x)=(X+x)
(40-x)=(16+x)
24 = 2x
x = 12
12 students must transfer to the more difficult, very early morning, class.
Answer:
Jeff finished first
Step-by-step explanation:
To solve this equation, I can either converts 2 minutes 2 seconds to seconds or convert 121 seconds to minutes
<u><em>CONVERT 2 MINUTES 2 SECONDS TO SECONDS</em></u>
60 seconds = 1 minutes
to convert 2 minutes 2 seconds to seconds, multiply 2 minutes by 60 and then add 2 seconds to it
2 x 60 = 120 seconds
120 seconds + 2 seconds = 122 seconds
Paul finished in 122 seconds while Jeff finished in 121 seconds. Jeff finished first
<u><em>CONVERT 121 SECONDS TO MINUTES</em></u>
60 seconds = 1 minutes
To convert 121 seconds to minutes, we have to divide by 60
121/60 = 2 minutes 1 second
Paul finished the race in 2 minutes 2 seconds while eff finished the race in 2 minutes 1 second. Jeff finished first
Subtract 12 from both sides
4(2x + 2) > 100 - 12
Simplify 100 - 12 to 88
4(2x + 2) > 88
Divide both sides by 4
2x + 2 > 88/4
Simplify 88/4 to 22
2x + 2 > 22
Subtract 2 from both sides
2x > 22 - 2
Simplify 22 - 2 to 20
2x > 20
Divide both sides by 2
x > 20/2
Simplify 20/2 to 10
<u>x > 10</u>
Answer:
N= -4
Step-by-step explanation:
Just divide both sides by 45.3 to isolate the variable (n).
Hope this helped :)
Answer:
Step-by-step explanation:
the problem is, there is no problem ;)
