Answer:
The commensal relationship between the sharks and remoras can be described as although remoras consume parasites, sharks with remoras show no better health or growth than sharks without remoras.
Explanation:
A commensal relationship refers to a relationship where two or more organisms in a habitat neither benefit or harm each other.
- The second option infers that the remoras harm the sharks. This is a parasitic relationship.
- The third option infers that the sharks are harmed by the remoras because the sharks depend on something that the remoras are limiting. This is also a parasitic relationship.
- The fourth option infers a commensal relationship, but falsely describes it. The relationship described by this option is a parasitic relationship (one benefits, the other does not).
Therefore, the answer is the first option: Although remoras consume parasites, sharks with remoras show no better health or growth than sharks without remoras.
Hey there!
Which substance is a nucleus acid?
Well here’s your answer:
Nucleic acids, which include DNA
(deoxyribonucleic acid) and RNA (ribonucleic acid), are made from monomers known as nucleotides. Each nucleotide has three components: a 5-carbon sugar, a. If the sugar is deoxyribose, the polymer is DNA.
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Reinassans. people left their nobles and started to become independant. this lead to buissens,trade,exporlation and discovery. sorry about my spelling.
Answer:
- Only fMet-tRNA(fMet) can bind first to the P site in the ribosome. ( A )
- There are more than one tRNA with the 5' CAU 3' anticodon. ( B )
- The N-formyl group attached to methionine prevents fMet from entering interior positions in a polypeptide. ( D )
Explanation:
The statements that explains how N--formyl methionine (fMet) is only associated with the 5' AUG initiation codon and not with internal AUG codons, given that methionine in both cases in encoded by an AUG in the mRNA are :
Only fMet-tRNA(fMet) can bind first to the P site in the ribosome. ( A )
There are more than one tRNA with the 5' CAU 3' anticodon. ( B )
The N-formyl group attached to methionine prevents fMet from entering interior positions in a polypeptide. ( D )
While statement C is wrong.
