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serg [7]
3 years ago
15

I need the answer to these problem...I’ve been stuck on it the most.

Mathematics
1 answer:
crimeas [40]3 years ago
8 0

Answer:

1. 2x + 30° = 180°

2x = 150°

x = 75°

2. (2x - 24)° + (x + 12)° + (x - 8)° = 180°

4x - 20 = 180°

4x = 200

x = 50°

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Parallelogram WXYZ and parallelogram W" X" Y" Z" are congruent.
Nadya [2.5K]
Reflections, rotations, and translations all change the location, but not the size or shape of the parallelogram.  Congruence describes the line lengths and angle sizes - all of which will be maintained.  Thus, reflections, rotations, and translations will maintain congruence.

All of the options use only reflection, rotation, and translation, so all of these could be the transformation in question.
3 0
3 years ago
Which angle pair is a pair of alternate exterior angles
neonofarm [45]

Answer:

A) angle 5and 4

hope it helps.

5 0
3 years ago
CAN SOMEONE HELP ME ANSWER THIS ?
kumpel [21]
Use gauthmath it can help u it’s any math work instead of waiting on here 3EMB3R use that code to get more tickets
7 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
lana [24]

The series and the sigma notations are\sum\limits^4_0 3(5)^n = 3 + 15 +75 + 375 +1875, \sum\limits^4_0 4(8)^n = 4 + 32 + 256+ 2048 + 16384, \sum\limits^4_0 2(3)^n = 2 + 6 + 18 + 54 + 162 and \sum\limits^4_0 5(3)^n = 5 + 15 + 45 + 135 + 405

<h3>How to match each series with the equivalent series written in sigma notation?</h3>

To do this, we simply expand each sigma notation.

So, we have:

\sum\limits^4_0 3(5)^n

Next, we set n = 0 to 4.

So, we have:

3(5)^0 = 3

3(5)^1 = 15

3(5)^2 = 75

3(5)^3 = 375

3(5)^4 = 1875

So, we have:

\sum\limits^4_0 3(5)^n = 3 + 15 +75 + 375 +1875

\sum\limits^4_0 4(8)^n

Next, we set n = 0 to 4.

So, we have:

4(8)^0 = 4

4(8)^1 = 32

4(8)^2 = 256

4(8)^3 = 2048

4(8)^4 = 16384

So, we have:

\sum\limits^4_0 4(8)^n = 4 + 32 + 256+ 2048 + 16384

\sum\limits^4_0 2(3)^n

Next, we set n = 0 to 4.

So, we have:

2(3)^0 = 2

2(3)^1 = 6

2(3)^2 = 18

2(3)^3 = 54

2(3)^4 = 162

So, we have:

\sum\limits^4_0 2(3)^n = 2 + 6 + 18 + 54 + 162

\sum\limits^4_0 5(3)^n

Next, we set n = 0 to 4.

So, we have:

5(3)^0 = 5

5(3)^1 = 15

5(3)^2 = 45

5(3)^3 = 135

5(3)^4 = 405

\sum\limits^4_0 5(3)^n = 5 + 15 + 45 + 135 + 405

Hence, the series and the sigma notations are\sum\limits^4_0 3(5)^n = 3 + 15 +75 + 375 +1875, \sum\limits^4_0 4(8)^n = 4 + 32 + 256+ 2048 + 16384, \sum\limits^4_0 2(3)^n = 2 + 6 + 18 + 54 + 162 and \sum\limits^4_0 5(3)^n = 5 + 15 + 45 + 135 + 405

Read more about sigma notation at:

brainly.com/question/542712

#SPJ1

8 0
2 years ago
Jasmine borrowed $15,000 for 8 years and she paid $6,600 in interest. What was the interest rate for Jasmine's loan?
weeeeeb [17]

Answer:

5.5%

Step-by-step explanation:

To find the interest rate, use the equation:  I = prt

I = Interest = $6,600

p = principal = $15,000

r = rate = unknown

t = time = 8 years


Now plug the numbers into the equation.

6,600 = 15,000 * r * 8

6,600 = 120,000 * r


Now isolate the variable by dividing both sides of the equation by 120,000.

0.055 = r


Now change the rate to a percent by moving the decimal point 2 digits to the right.

5.5% = r   OR   r = 5.5%

4 0
3 years ago
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