sides of right angle triangle follows Pythagoras theroem
which states
a^2 +b^2 = c^2
where a , b and c are sides of right angle triangle.
here none of options do not follow this.
so answer is option D
Answer:
a) P(Y > 76) = 0.0122
b) i) P(both of them will be more than 76 inches tall) = 0.00015
ii) P(Y > 76) = 0.0007
Step-by-step explanation:
Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
To find - (a) If a man is chosen at random from the population, find
the probability that he will be more than 76 inches tall.
(b) If two men are chosen at random from the population, find
the probability that
(i) both of them will be more than 76 inches tall;
(ii) their mean height will be more than 76 inches.
Proof -
a)
P(Y > 76) = P(Y - mean > 76 - mean)
= P(
) >
)
= P(Z >
)
= P(Z >
)
= P(Z > 2.25)
= 1 - P(Z ≤ 2.25)
= 0.0122
⇒P(Y > 76) = 0.0122
b)
(i)
P(both of them will be more than 76 inches tall) = (0.0122)²
= 0.00015
⇒P(both of them will be more than 76 inches tall) = 0.00015
(ii)
Given that,
Mean = 69.7,
= 1.979899,
Now,
P(Y > 76) = P(Y - mean > 76 - mean)
= P(
)) >
)
= P(Z >
)
= P(Z >
))
= P(Z > 3.182)
= 1 - P(Z ≤ 3.182)
= 0.0007
⇒P(Y > 76) = 0.0007
Answer:
100
Step-by-step explanation:
94 bagels in total. 100 will be plenty
Answer:
$10.25
Step-by-step explanation:
Set up a system of equations, so 3c + 2m = 7 and 2c + 4m = 8, where c = the cost of coffees, and m = cost of muffins
To solve multiply the first equation by -2(3c + 2m=7) so you get -6c -4m = -14 now add the two equations
-6c - 4m = -14
2c + 4m = 8 notice that -6c + 2c = -4c and -4m + 4m cancels, then -14+8=-6
so we have -4c = -6 so c = $1.50
To solve for m, substitute c = 1.50 so 3(1.50) + 2m = 7, so solve for m so
4.5 + 2m = 7, 2m = 2.5, so m = $1.25
So now solve the final problem 6(1.50) + 1(1.25) = $10.25
Answer: <span>A square inscribed in a circle.
</span>
Justification:
Note that by making two perpendicular lines that intersect each other in the center of the circle, he obtains 4 equidistant points on the circumference.
So, joining each pair of neighbouring points, the image will reveal 4 congruent sides joining at right angles (90°). This is the image of a square with the four vertices on the circumference.