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77julia77 [94]
2 years ago
13

3m - 3 divided by 3 for m=8

Mathematics
2 answers:
KengaRu [80]2 years ago
6 0

Answer:

Either 7 or 23 - read note

Step-by-step explanation:

Substitute m for 8.

*Note: I'm not sure if anything is in parentheses so there are two possible answers depending on whether you want it done left to right or by order of operations*

Left to Right:

3(8) - 3 ÷ 3

24 - 3 ÷ 3

21 ÷ 3

7

Order of Operations:

3(8) - 3 ÷ 3

24 - 3 ÷ 3

24 - 1

23

xxMikexx [17]2 years ago
5 0
For m = 8

3m - 3/3
3(8) - 3/3
24 - 1
= 23

3/3 is the same thing as 1
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the coordinates of a pentagon ABCDE are A(-5,4),B (1,4),C(1,-1), D(-2,-5) and E(-5,-1) what is the perimeter of the pentagon
kogti [31]
Perimeter is a continuous line forming the boundary of a closed geometrical figure. perimeter of a pentagon = AB+BC+CD+DE+EA (that is 5 sided figure) 
so my plan is easy but effective, calculate all those distances using those coordinates with the aid of distance formular. then you add those distances algebraically .
7 0
3 years ago
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The stopping distance, D, in feet of a car is directly proportional to the square of it's speed, V. Write the direct variation e
kow [346]

Answer:

D=kV^2

Step-by-step explanation:

In this problem, it is given that,

The stopping distance, D, in feet of a car is directly proportional to the square of it's speed, V.

We need to write the direct variation equation for the scenario above. It can be given by :

D\propto V^2

To remove the constant of proportionality, we put k.

D=kV^2

k is any constant

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Multiply the numerators together. Multiply the denominators together. Then reduce if necessary.

\dfrac{first~numerator}{first~denominator} \times \dfrac{second~numerator}{second~denominator} = \dfrac{(first~numerator)\times(second~numerator)}{(first~denominator)\times(second~denominator)}

\dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{a \times c}{b \times d}

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\\ \sf\longmapsto A=(1-4)-(2+1)

\\ \sf\longmapsto A=-3-3

\\ \sf\longmapsto A=-6

\\ \sf\longmapsto B=(3-\dfrac{1}{2})-(2-4)

\\ \sf\longmapsto B=\left(\dfrac{5}{2}\right)+2

\\ \sf\longmapsto B=\dfrac{5+4}{2}

\\ \sf\longmapsto B=\dfrac{9}{2}

Now

\\ \sf\longmapsto AB=-6\times \dfrac{9}{2}

\\ \sf\longmapsto AB=-3(9)

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BA

\\ \sf\longmapsto \dfrac{9}{2}\times (-6)

\\ \sf\longmapsto 9(-3)

\\ \sf\longmapsto -27

Observed:-

\\ \sf\longmapsto AB=BA

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