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irinina [24]
3 years ago
12

GIVING BRAINLIEST IF CORRECT PLEASE HELP ASA[P

Mathematics
1 answer:
Vitek1552 [10]3 years ago
3 0

Answer:

A) b= 8 students

B)  1) 19/55   2) 28/55

Step-by-step explanation:

I'm sorry if I'm getting this whole concept wrong cause it felt way too easy to be right so I'm sorry if you get it wrong.

The reason the first question is 8 is because of the fact that you first have to add the students charted on the Venn-diagram and subtract that from 55, getting you to 8 students.

For the second one, the first part would be 19/55 becuase in the Venn-diagram it is shown that only 19 people passed both and so that be the numerator and the denominator would be the total of students, so it would be 55.

Same thing for part two except the fact that you have to add the students who only passed one subject, so combine 17 and 11, getting you to 28, thus getting the answer 28/55.  

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PERMUTATION:
horsena [70]

Answer:

28

Step-by-step explanation:

It can be a one digit no.

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2C1 = 2 (only two even options available)

It can be a 2 digit no.

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The last digit has to be even for the no. to be even.

2C1 × 4C1 = 8 (2C1 for the last digit, 4C1 for the first)

It can be a 3 digit no.

_ _ _

First digit has to be less than 5 to be less than 500, and the last digit has to be even.

1) 2/4 _ 4

2C1 × 3C1 = 6 (2C1 to choose between 2 and 4, 3C1 for the second digit)

2) 1/3 _ 2/4

2C1 × 3C1 × 2C1 = 12 (2C1 to choose between 1 and 3, 3C1 for the second digit, 2C1 to choose between 2 and 4)

Total = 2 + 8 + (6 + 12)

= 28

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